A string vibrates with a particular fundamental frequency. It is possible, however, to produce pitches with different frequencies from the same string. The four properties of the string that affect its frequency are length, diameter, tension, and density.
The frequency f = 1/T = v/λ. So f = v/λ. We also saw that, for the fundamental frequency f1, the string length is λ/2, so f1 = v/2L. The wave speed is determined by the string tension F and the mass per unit lenght or linear density μ = M/L, v = (F/μ)1/2 = (FL/M)1/2.
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12N because you are just adding those two up on the same side
Answer:
Length of cable = 16.7 m
Distance from ground = 15.4
New angle between pole and cable = 58.5 degrees
Explanation:
The flagpole forms a right-angled triangle with the cable and the ground.
Let the adjacent side be the flagpole, the hypotenuse be the cable and the ground be the opposite side.
hypotenuse = h
adjacent = 6.8 m
distance from ground = d
angle = 66.0
cos 66 = 6.8/h
h = 6.8/cos 66
h = 16.7 m
tan 66 = d /6.8
d = 6.8 * tan 66
d = 15.3 m
If the cable is brought 4.2 m closer to the pole, new distance = 15.3 - 4.2 = 11.1 m
let new angle be x
tan x = 11.1/6.8
x = tan⁻¹ (11.1/6.8)
x = 58.5 degrees
5.16 meters!!!!!!!!!!!!!!!!!!!!