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sveta [45]
3 years ago
9

An object is falling under the influence of gravity in presence of air resistance . There are two forces acting on it. (i) What

are these two forces? (ii)Explain why will the object start moving with uniform velocity after some time?
Physics
1 answer:
MatroZZZ [7]3 years ago
8 0

Answer:

1 the forces are:friction, gravitational pull

2.i guess due to uniform change in displacement per unit time therefore uniform acceleration

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When heat is removed from a gas the gas will eventually
Lostsunrise [7]
The answer should be B, Condense.

Freezing is when a liquid transforms into a solid.
Sublimation is when a solid goes straight to a gas.
Evaporation is when a liquid transforms into a gas.
8 0
3 years ago
Read 2 more answers
4. Describe how the velocity of an object changes if it undergoes uniformly acceleration motion. Can its direction change?
valentinak56 [21]

Answer:

n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

Explanation:

Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.

In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.

              a_{t} = (v₂-v₁)/Δt

In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.

                    a_{c} = v2/R

In the general case, both the module and the address change

             a = Ra (  a_{t}^2 +   a_{c}^2)  

4 0
3 years ago
A 75 kg baseball player runs at a velocity of 6 m/s before sliding to a stop at second base. a. What is the kinetic energy of th
lana [24]

Answer:

a. \displaystyle k_o=1350\ J

b. \displaystyle k_1=0\ J

c. \Delta k=-1350\ J

d. W=-1350\ J

e. F=-675\ N

Explanation:

<u>Work and Kinetic Energy </u>

When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:

\Delta k=k_1-k_0

Knowing that

\displaystyle k=\frac{mv^2}{2}

We have

\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}

The work done by the force who caused the change of velocity (acceleration) is

\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}

If we know the distance x traveled by the object, the work can also be calculated by

W=F.x

Being F the force responsible for the change of velocity

The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops

a. Before the slide, his initial kinetic energy is

\displaystyle k_o=\frac{mv_0^2}{2}

\displaystyle k_o=\frac{(75)6^2}{2}

\boxed{\displaystyle k_o=1350\ J}

b. Once he reaches the base, the player is at rest, thus his final kinetic energy is

\displaystyle k_1=\frac{(75)0^2}{2}

\boxed{\displaystyle k_1=0\ J}

c. The change of kinetic energy is

\Delta k=k_1-k_0=0\ J-1350\ J

\boxed{\Delta k=-1350\ J}

d. The work done by friction to stop the player is

W=\Delta k=k_1-k_0

\boxed{W=-1350\ J}

e. We compute the force of friction by using

W=F.x

and solving for x

\displaystyle F=\frac{W}{x}

\displaystyle F=\frac{-1350\ J}{2\ m}

\boxed{F=-675\ N}

The negative sign indicates the force is against movement

6 0
3 years ago
Justin is riding his bike up Dunmore Hill. The effort force from his feet on his pedals is 1160N.
Schach [20]

Explanation:

the answer is 1835N that how best I can help

3 0
2 years ago
A truck is traveling at 27 m/s down the interstate highway where you are changing a flat tire. frequency of 185 Hz.
Reil [10]

Answer:

(a) the observed frequency is 200 Hz

(b) the observed frequency is 188 Hz.

Explanation:

speed of the truck, Vs = 27 m/s

frequency of the truck as it approaches, Fs = 185 Hz

(a) Apply Doppler effect to determine the frequency you will hear.

As the truck approaches you, the observed frequency will be higher than the source frequency because of decrease in distance.

F_s = F_o [\frac{V}{V_S + V} ]

Where;

Fo is the observed frequency which is the frequency you will hear.

V is speed of sound in air

F_s = F_o [\frac{V}{V_S + V} ]\\\\185 = F_o [\frac{340}{27 + 340} ]\\\\185 = F_o (0.926)\\\\F_o = \frac{185}{0.926}\\\\F_o = 199.78 \ Hz

F_o = 200 \ Hz

(b) Apply the following formula for a moving observer and a moving source;

F_o = F_s[\frac{V-V_o}{V} ](\frac{V}{V-V_S} )

The observed frequency is negative since you are driving away from the truck and the source frequency is also negative since it is driving towards you.

F_o = F_s[\frac{V-V_o}{V} ](\frac{V}{V-V_S} )\\\\F_o = 185[\frac{340-22}{340} ](\frac{340}{340-27} )\\\\F_o = 185(0.9353)(1.0863)\\\\F_o = 188 \ Hz

5 0
3 years ago
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