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velikii [3]
3 years ago
12

Suppose you want to represent the velocity of a BALL with respect to a particular frame of reference from aboard a moving TRAIN.

You would most likely write the velocity of the ball using the symbol v with the subscript(s):_________
Physics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

Explanation:

We would most likely write the velocity of the ball as follow :

V(b<em>all</em> with respect to t<em>rain)</em> = Vbt

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A car has uniform velocity of 108km/hour. How far does it travel in 1 1/2 minutes
Nostrana [21]

Answer:

2.7km

Explanation:

Two methods: Convert km/hour to km/minutes or convert 3/2 minutes to hours.

Then multiply time to get the distance of the car traveled.

3 0
3 years ago
A scientist wants to model an internal organ with connective tissue as a mass on a spring. The mass of the organ is 2.0 kg, and
vichka [17]

Answer:

Spring constant, k = 5483.11 N/m

Explanation:

It is given that,

Mass of the organ, m = 2 kg

The natural period of oscillation is, T = 0.12 s

Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

k=\dfrac{4\pi^2 m}{T^2}

k=\dfrac{4\pi^2 \times 2\ kg}{(0.12\ s)^2}

k = 5483.11 N/m

So, the  spring constant for the spring in the scientist's model is 5483.11 N/m.

5 0
3 years ago
I have no idea what to do. Plz help!
aleksklad [387]
Work is (force) times (distance). For Amy, you know both of them, and you can easily multiply them to find the amount of work. For Joe, the distance is zero, which should tell you all you need to know.
7 0
3 years ago
What is the magnitude of the electric force of attraction between two point charges + 2.8 mc and -1.2 mc if the distance
Anit [1.1K]

Answer:

a

Explanation:

it just a

8 0
3 years ago
A 2000 kg car experiences a braking force of 10000N and skids to a 14 m stop. What was the speed of the car just before the brak
Fudgin [204]

Answer:

V = 11.83 m/s

Explanation:

Given the following data;

Mass = 2000 kg

Force = 10000N

Distance = 14 m

To find the final velocity of the car;

First of all, we would determine the acceleration of the car;

Acceleration = force/mass

Acceleration = 10000/2000

Acceleration = 5 m/s²

Next, we would use the third equation of motion to find the final velocity;

V^{2} = U^{2} + 2aS

Where;

V represents the final velocity measured in meter per seconds.

U represents the initial velocity measured in meter per seconds.

a represents acceleration measured in meters per seconds square.

S represents the displacement measured in meters.

Substituting into the equation, we have;

V² = 0² + 2*5*14

V² = 0 + 140

V = √140

V = 11.83 m/s

5 0
3 years ago
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