A solid insulating sphere of radius R = 1.0 m that carries a positive charge Q1 = 1.0 mC uniformly distributed over it is concen
tric with a very thin insulating shell of radius 2R that carries the charge Q2 = -1.0 mC. The charge Q2 is distributed uniformly over the shell.
Use Gauss's law to obtain the magnitude of the electric field:
a. E1 inside the sphere, r < R
b. E2 between the sphere and the shell, R < r < 2R
c. E3 outside the shell, r > 2R
d. Plot the electric field in the radial direction on a graph. Be sure to label the actual magnitude of the electric field at r = 0, r= R, and r = 2R.
Use Gauss's law to obtain the magnitude of the electric field:
a. E1 inside the sphere, r < R
b. E2 between the sphere and the shell, R < r < 2R
c. E3 outside the shell, r > 2R
d. Plot the electric field in the radial direction on a graph. Be sure to label the actual magnitude of the electric field at r = 0, r= R, and r = 2R.
1 answer:
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Answer:
4 A
Explanation:
We are given that
I=12 A
We have to find the current flowing through each resistor.
We know that in parallel combination current flowing through different resistors are different and potential difference across each resistor is same.
Formula :
Using the formula
Substitute the values
Hence, current flows through any one of the resistors is 4 A.
Answer:
The right solution is "24.39 per sec".
Explanation:
According to the question,
⇒
The time will be:
⇒
hence,
⇒