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zzz [600]
4 years ago
8

A 0.5 kg ball travelling at a velocity of 1 m/s collides with a 1.5 kg ball at rest, calculate the

Physics
1 answer:
irakobra [83]4 years ago
5 0

Answer:

0.25m/s

Explanation:

Mass, m1 = 0.5kg

m2= 1.5kg

Velocity before collision for mass 1, u1 = 1m/s

Velocity before collision for mass 2, u2 = 0m/s because it is at rest.

Velocity after collision, V = ?

From law of conservation of linear momentum

Sum of momentum before collision = sum of momentum after collision.

Remember momentum = mass x velocity

Therefore,

m1u1 +m2u2 = (m1 + m2)V

0.5x1 + 1.5x0 = (1.5+0.5)V

0.5+0 = 2V

2V = 0.5

Divide both sides by 2

V = 0.5/2

V = 0.25m/s

I hope this was helpful, Please mark as brainliest

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Answer:

The tension increases by a factor of 8

Explanation:

We know that the tension, T in the string equals the centripetal force on the ball. So

T = mrω² = mr(2πf)² = 4mrπ²f² where m = mass of ball, r = radius of circle and f = frequency of rotation

If the radius and frequency are doubled, then r = 2r and f = 2f. So, the new tension is T' = 4mr'π²f'² = 4m(2r)π²(2f)² = 4 × 2 × 4mrπ²f² = 8T  

Since T' = 8T,

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A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t
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Answer:

T=66262.4s

Explanation:

From the question we are told that:

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Generally the equation for Satellite Speed is mathematically given by

V=(\frac{GM}{d} )^{0.5}

V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}

V=3354.83m/s

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