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3 years ago

A 0.5 kg ball travelling at a velocity of 1 m/s collides with a 1.5 kg ball at rest, calculate the

Physics

1 answer:

irakobra [83]3 years ago

5 0

Answer:

0.25m/s

Explanation:

Mass, m1 = 0.5kg

m2= 1.5kg

Velocity before collision for mass 1, u1 = 1m/s

Velocity before collision for mass 2, u2 = 0m/s because it is at rest.

Velocity after collision, V = ?

From law of conservation of linear momentum

Sum of momentum before collision = sum of momentum after collision.

Remember momentum = mass x velocity

Therefore,

m1u1 +m2u2 = (m1 + m2)V

0.5x1 + 1.5x0 = (1.5+0.5)V

0.5+0 = 2V

2V = 0.5

Divide both sides by 2

V = 0.5/2

V = 0.25m/s

I hope this was helpful, Please mark as brainliest

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One hundred turns of insulated copper wire are wrapped around an iron core of cross-sectional area 0.100m2. As the magnetic fiel

bagirrra123 [75]

Answer:

The voltage induced in the coil is 1.25 V.

Explanation:

Given;

number of turns, N = 100 turns

cross sectional area of the copper coil, A = 0.1 m²

initial magnetic field, B₁ = 0.5 T

final magnetic field, B₂ = 1.00 T

duration of change in magnetic field, dt = 4 s

The induced emf in the coil is calculated as;

$emf = -N\frac{\delta \phi}{\delta t} \\\\emf = - N (\frac{\delta B}{\delta t}) A\\\\emf = -N (\frac{B_1 -B_2}{\delta t} )A\\\\emf = N(\frac{B_2-B_1}{\delta t} )A\\\\emf = 100(\frac{1-0.5}{4} )0.1\\\\emf = 1.25 \ Volts$

Therefore, the voltage induced in the coil is 1.25 V.

6 0

3 years ago

Deduce an expression for the gravitational potential

bonufazy [111]

M*g*h

G is the gravity which is usually a fixed number (10)

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3 years ago

A projectile is launched vertically from the surface of the Moon with an initial speed of 1360 m/s. At what altitude is the proj

LenaWriter [7]

Answer:

485520 m

Explanation:

$v_{o}$ = initial velocity of the projectile = 1360 m/s

$v_{f}$ = final velocity of the projectile = $\left ( \frac{2}{5} \right )v_{_{o}}$ = $\left ( \frac{2}{5} \right )(1360)$ = 544 m/s

a = acceleraton due to gravity on moon = - 1.6 m/s²

h = Altitude of the projectile

Using the kinematics equation

$v_{f}^{2} = v_{o}^{2} + 2 a h$

Inserting the values

$544^{2} = 1360^{2} + 2 (-1.6) h$

h = 485520 m

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3 years ago

;p;p;p;p;p;p;p;p;lol

Pachacha [2.7K]

Answer:

lol, I like math. and this question is awesome. lol.

Explanation:

So I like math because I am good at it. I hate ELA bc im bad at it.

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3 years ago

R=70<br> R-40<br> M<br> 120V<br> R, 90<br> W

Keith_Richards [23]

Answer:

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2 years ago