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Gekata [30.6K]
3 years ago
14

Characteristics we use to tell the differences between kinds of matter pare called _ properties

Physics
1 answer:
lorasvet [3.4K]3 years ago
6 0

The answer to the blank is physical.

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Three small masses are positioned as follows: 2.0 kg at (0.0 m, 0.0 m), 2.0 kg at (2.0 m, 0.0 m), and 4.0 kg at (2.0 m, 1.0 m).
melamori03 [73]
Refer to the diagram shown below.

The given data is

mass, kg   Coordinates. m
-------------   -----------------
   2               (0, 0)
   2               (2, 0)
   4               (2, 1)

Total mass, M = 2+2+4 = 8kg
Let (x,y) be the coordinates of M.

Then, taking moments about the origin, we obtain
8x = 2*0 + 2*2 + 4*2 = 12
x = 1.5 m

8y = 2*0 + 2*0 + 4*1 = 4
y = 0.5 m

Answer:  (1.5, 0.5) m




6 0
3 years ago
What is the difference between: first moment of area and second moment of area?
zhannawk [14.2K]
To determine the centroid of the object first moment of area is used.

To predict the resistance of a shape to bending and deflection which are directly proportional, second moment of area is used.

6 0
3 years ago
What controls how fast an object falls?
Vedmedyk [2.9K]

Answer:

gravity

Explanation:

as the earth rotates on an axis, it causes an effect known as centripetal acceleration with is an acceleration that pulls objects towards the center of the object. in planets, we call this Gravity

5 0
2 years ago
Read 2 more answers
The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?
Nina [5.8K]
It is the photosphere
5 0
3 years ago
Consider a step-down transformer with 15 turns in the primary and 6 turns in the secondary windings. Calculate the input impedan
AURORKA [14]

Answer:

Input impedance of this transformer is 50 ohms.  

Explanation:

Given that,

Number of turns in the primary coil, N_p=15

Number of turns in the secondary coil, N_s=6

Output impedance of the transformer, V_o=8\ \Omega

The number of turns and the impedance ratio in the step down transformer is given by :

\dfrac{15}{6}=\sqrt{\dfrac{Z_p}{Z_s}}\\\\\dfrac{15}{6}=\sqrt{\dfrac{Z_p}{8}}\\\\Z_p=50\ \Omega

So, the input impedance of this transformer is 50 ohms. Hence, this is the required solution.

8 0
3 years ago
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