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3 years ago

If the mass of a material is 99 grams and the volume of the material is 22 cm3, what would the density of the material be?

1 answer:

7 0

You are asked to give the answer in g/cm3. So without knowing any single formulae you can just divide grams by cm3.

 $\frac{99 grams}{22 cm^{3} }$

= 4.5 g/cm3

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Alexandria became the center for _____. its science

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Alexandria became the center for Hellenistic scholarship and culture. It was a great revolution in learning during this era as Alexandria had a library filled with books and important documents which were copied and even stolen. Over 500,000 titles were present in Alexandria's library.

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3 years ago

Which planet has the closest gravitational pull to earth

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Answer:

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2 years ago

You charge an initially uncharged 65.7-mf capacitor through a 39.1-Ï resistor by means of a 9.00-v battery having negligible int

uysha [10]

In a RC-circuit, with the capacitor initially uncharged, when we connect the battery to the circuit the charge on the capacitor starts to increase following the law:
$Q(t) = Q_0 (1-e^{-t/\tau})$
where t is the time, $Q_0 = CV$ is the maximum charge on the capacitor at voltage V, and $\tau = RC$ is the time constant of the circuit.
Using this law, we can answer all the three questions of the problem.

1) Using $R=39.1 \Omega$ and $C= 65.7 mF=65.7\cdot 10^{-3}F$ , the time constant of the circuit is:
$\tau = RC=(39.1 \Omega)(65.7 \cdot 10^{-3}F)=2.57 s$

2) To find the charge on the capacitor at time $t=1.95 \tau$ , we must find before the maximum charge on the capacitor, which is
$Q_0 = CV=(65.7 \cdot 10^{-3}F)(9 V)=0.59 C$
And then, the charge at time $t=1.95 \tau$ is equal to
$Q(1.95 \tau) = Q_0 (1-e^{-t/\tau})=(0.59 C)(1-e^{-1.95})=0.51 C$

3) After a long time (let's say much larger than the time constant of the circuit), the capacitor will be fully charged, this means its charge will be $Q_0 = 0.59 C$ . We can see this also from the previous formule, by using $t=\infty$ :
$Q(t) = Q_0 (1-e^{-\infty})=Q_0(1-0) = 0.59 C$

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3 years ago

How does the mass of an object affect the outcome when an unbalanced force acts on it?

Verdich [7]

Answer:

The magnitude of acceleration is reduced.

Explanation:

Force is defined as push or pull

The force is said to be balance force if the force are equal in size but opposite in direction. ie the object does not move or move with constant speed.

The force are to be unbalanced force if the force cause change in motion. ie the object has force greater than zero and has acceleration.

According to Newton second law of motion , acceleration depends on force acting on the object and mass of object.

F=ma

a= $\frac{F}{m}$

When unbalanced force act on the mass of object it reduces magnitude of acceleration without changing the direction.

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3 years ago