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7nadin3 [17]
3 years ago
5

A 10-kg rock and a 20kg rock are dropped at the same time and experience no significant air resistance. If the rock falls with a

cceleration a, what is the acceleration of the 20-kg rock?
Physics
1 answer:
Ierofanga [76]3 years ago
6 0

The acceleration of the 20-kg rock is, also, a. Hope this helps.

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Will give brainlist.
Lera25 [3.4K]

Answer:

<u>Displacement (km)</u>

Explanation:

The y axis is the vertical axis pointing up and down. This is labeled as the the displacement (km) in the graph.

6 0
3 years ago
Is the relationship between the length of a pendulum and its period is valid at all times?
Stels [109]
Yes it is valid all the times under the consideration of acceleration due to gravity .it is not valid on space where there is no influence of gravity
4 0
3 years ago
At which part of its orbit is the planet traveling at the slowest speed?<br> A, B, C, or D
Natali [406]
I think its D im not sure tho
3 0
3 years ago
Read 2 more answers
A torsional pendulum consists of a disk of mass 450 g and radius 3.5 cm, hanging from a wire. If the disk is given an initial an
Montano1993 [528]

To solve this problem we will use the kinematic equations of angular motion, starting from the definition of angular velocity in terms of frequency, to verify the angular displacement and its respective derivative, let's start:

\omega = 2\pi f

\omega = 2\pi (2.5)

\omega = 5\pi rad/s

The angular displacement is given as the form:

\theta (t) = \theta_0 cos(\omega t)

In the equlibrium we have to t=0, \theta(t) = \theta_0 and in the given position we have to

\theta(t) = \theta_0 cos(5\pi t)

Derived the expression we will have the equivalent to angular velocity

\frac{d\theta}{dt} = 2.7rad/s

Replacing,

\theta_0(sin(5\pi t))5\pi = 2.7

Finally

\theta_0 = \frac{2.7}{5\pi}rad = 9.848\°

Therefore the maximum angular displacement is 9.848°

6 0
3 years ago
Please help me ; - ;
Irina18 [472]

Answer:

2 = C

3 = B

1 = A

Explanation:

5 0
3 years ago
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