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Greeley [361]
3 years ago
6

1. A large turbine has an initial angular momentum of 6700 kgm^2/s. A storm is rolling in and the wind picks up. 8 seconds later

the angular momentum of the turbine is 8800 kgm^2/s. What is the torque acting on the turbine
Physics
1 answer:
LekaFEV [45]3 years ago
4 0

Answer:

262.5 Nm

Explanation:

Torque is the rate of change of angular momentum.

Hence, we have

\tau = \dfrac{\Delta L}{t}

Δ<em>L</em> is the change in angular momentum.

Using values in the question,

\tau = \dfrac{8800-6700 \text{ kg m}^2\text{/s}}{8\text{ s}}  = 262.5 \text{ Nm}

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To understand the interplay of observations and models you must first be able to distinguish between things that we observe and
Svetllana [295]

Answer: a) Observation

b) observation

c) observation

d) observation

e) inference

f) inference

g) inference

h) inference

Explanation:

observation: The photosphere is made mostly of hydrogen and helium,The photosphere emits mostly visible light,The corona is hotter than the photosphere, The Sun emits neurtrinos

inferences: The Sun generates energy by fusing hydrogen into helium,The core temperature is 10 million k, The convection zone is cooler than the radiation zone,The composition of the photosphere is the same as that the gas cloud that have birth to our solar system.

3 0
3 years ago
Suppose A=BnCm, where A has dimensions LT, B has dimensions L2T-1, and C has dimensions LT2. Then the exponents n and m have the
julsineya [31]

Explanation:

The expression is :

A=B^nC^m

A =[LT], B=[L²T⁻¹], C=[LT²]

Using dimensional of A, B and C in above formula. So,

A=B^nC^m\\\\\ [LT]=[L^2T^{-1}]^n[LT^2}]^m\\\\\ [LT]=L^{2n}T^{-n}L^mT^{2m}\\\\\ [LT]=L^{2n+m}T^{2m-n}

Comparing the powers both sides,

2n+m=1 ...(1)

2m-n=1 ...(2)

Now, solving equation (1) and (2) we get :

n=\dfrac{1}{5}\\\\m=\dfrac{3}{5}

Hence, the correct option is (E).

5 0
3 years ago
Coulomb's Law: Two identical small charged spheres are a certain distance apart, and each one initially experiences an electrost
Ahat [919]

Answer:

The magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force. ( ¹/₄ F)

Explanation:

The electrostatic force between two charges is given by Coulomb's law;

F = \frac{kQ_1Q_2}{r^2}

where;

Q₁ and Q₂ are the magnitude of the charges

r is the distance between the charges

k is Coulomb's constant

Since the charges are identical;

Q₁ = Q

Q₂ = Q

the electrostatic force experienced by each charge is given by;

F =  \frac{kQ^2}{r^2}

When each of the spheres has lost half of its initial charge;

Q₁ = Q/2

Q₂ = Q/2

F_2 = \frac{k(Q/2)(Q/2)}{r^2}\\\\ F_2 = \frac{k(Q)(Q)}{4r^2}\\\\F_2 = \frac{1}{4} (\frac{kQ^2}{r^2} )\\\\F_2 = \frac{1}{4} (F)

Therefore, the magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force.

6 0
2 years ago
Alpha Particles
UNO [17]

Alpha > Beta > Gamma

Explanation:

Alpha particles are the heaviest radiation whereas gamma rays are the lightest.

An alpha particle closely resembles a helium particle.

Beta particles are similar to electrons in nature

Gamma rays have no weight. They are just rays.

  Alpha particles have a mass of  4.0012amu which is that of helium

  Beta particles have a mass of 5.5 x 10⁻⁴ amu

   Gamma rays have no mass.

Learn more:

Electromagnetic radiations brainly.com/question/6818046

#learnwithBrainly

7 0
3 years ago
Read 2 more answers
The intensity of sunlight at the earth surface is about 1000wlm2. The average temperature of the earth is about 58°
Nadya [2.5K]

The emissivity of the earth is 0.5

The emissivity of the earth is calculated by the Stefan's law

q= sigma a curlyepsilon T^(4)1000=5.67*10^(-8)*4 pi *(6400*10^(3))^(2)* curlyepsilon *288^(4) curlyepsilon =0.5

8 0
2 years ago
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