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Artemon [7]
2 years ago
9

Nearly of women who had recently given birth screen positive for peripartum onset depression.

Physics
2 answers:
andreyandreev [35.5K]2 years ago
7 0
B because the peripartum is the onset depression
vodomira [7]2 years ago
7 0
The answer is B, 45%
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gravity is a force between any two objects with mass. why doesn't a person feel a gravitational force between him/herself and an
antiseptic1488 [7]

Answer:

c)the gravitational forces of people is so small it is overshadowed by that of earth.

Explanation:

The gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the masses of the two objects

r is the distance between the two objects

From the formula, we see that the gravitational force depends on the masses of the objects: since the mass of the Earth (5.97\cdot 10^{24} kg is much much larger than the average mass of one person (80-100 kg), then the gravitational force exerted by the Earth on a person is also much much larger than the gravitational force between two people.

4 0
3 years ago
Read 2 more answers
How do you find period when you have frequency
nydimaria [60]

Period and frequency are mutual reciprocals.

Period = 1 / frequency .

Frequency = 1 / period

(Frequency) x (Period) = 1


8 0
3 years ago
The sun emits electromagnetic waves with a power of 4.0 × 10²⁶ W. Determine the intensity of electromagnetic waves from the sun
Sphinxa [80]

Answer:

I_v = 2,700 W / m^2

I_m = 610 W / m^2

I_s = 16 W / m^2

Explanation:

Given:

- The Power of EM waves emitted by Sun P_s = 4.0*10^26 W

- Radius of Venus r_v = 1.08 * 10^11 m

- Radius of Mars r_m = 2.28 * 10^11 m

- Radius of Saturn r_s = 1.43 * 10^12 m

Find:

Determine the intensity of electromagnetic waves from the sun just outside the atmospheres of (a) Venus, (b) Mars, and (c) Saturn.

Solution:

- We know that Power is related to intensity and surface area of an object follows:

                                        I = P / 4*pi*r^2

Where, A is the surface area of a sphere models the atmosphere around the planets.

a)

- The intensity at the surface of Venus is calculated as:

                                       I_v = P_s / 4*pi*r^2_v

                                       I_v = 4.0*10^26 / 4*pi*(1.08*10^11)^2

                                       I_v = 2,700 W / m^2

b)

- The intensity at the surface of Mars is calculated as:

                                       I_m = P_s / 4*pi*r^2_m

                                       I_m = 4.0*10^26 / 4*pi*(2.28*10^11)^2

                                      I_m = 610 W / m^2

c)

- The intensity at the surface of Saturn is calculated as:

                                       I_s = P_s / 4*pi*r^2_s

                                       I_s = 4.0*10^26 / 4*pi*(1.43*10^12)^2

                                      I_s = 16 W / m^2

7 0
3 years ago
While playing her guitar , karen plucks one string with increasing levels of force. What effect does this have on the sound prod
Lena [83]

Answer:

The amplitude of vibration of string will increase due to which loudness of sound will increase

Explanation:

As we know that the guitar is based on the principle of Resonance. When string of the guitar vibrates at a given frequency then the sound produced in the hollow part of the guitar will also be at same frequency.

This is known as resonance condition, so guitar will produce same frequency sound as that of frequency of string.

Now if the string is plucked with increasing level of force then it will increase the amplitude of vibrations of the string due to which the sound produced in the guitar will also be of same level.

So here we can say that amplitude and intensity of sound related as

I = kA^2

so on increasing amplitude the intensity will increase and hence it will produce loud sound

8 0
3 years ago
Read 2 more answers
What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?
vfiekz [6]

V = 99 volts

Explanation:

The voltage drop can be calculated using Ohm's law:

V = IR

= (1.10 A)(90 Ω)

= 99 volts

8 0
2 years ago
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