1) In any collision the momentum is conserved
(2*m)*(vo) + (m)*(-2*vo) = (2*m)(v1') + (m)(v2')
candel all the m factors (because they appear in all the terms on both sides of the equation)
2(vo) - 2(vo) = 2(v1') + (v2') => 2(v1') + v(2') = 0 => (v2') = - 2(v1')
2) Elastic collision => conservation of energy
=> [1/2] (2*m) (vo)^2 + [1/2](m)*(2*vo)^2 = [1/2](2*m)(v1')^2 + [1/2](m)(v2')^2
cancel all the 1/2 and m factors =>
2(vo)^2 + 4(vo)^2 = 2(v1')^2 + (v2')^2 =>
4(vo)^2 = 2(v1')^2 + (v2')^2
now replace (v2') = -2(v1')
=> 4(vo)^2 = 2(v1')^2 + [-2(v1')]^2 = 2(v1')^2 + 4(v1')^2 = 6(v1')^2 =>
(v1')^2 = [4/6] (vo)^2 =>
(v1')^2 = [2/3] (vo)^2 =>
(v1') = [√(2/3)]*(vo)
Answer: (v1') = [√(2/3)]*(vo)
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Answer:
By energy efficient, if you mean LED, no the lamp will not flow like normal. If the bulb is still an incandescent but slightly lower wattage, it will take a little longer to get going. Lava lamps require heat and light for the effect to work.
The correct answer is low resistance.
A heating element's resistance is neither "extremely high" nor "very low." Since the amount of heat produced by the circuit is proportional to the current, the resistance of the heating element must be low enough to draw the necessary current. Thus, low resistance is the general characteristic of electrical devices like warmers, toasters, and heating pads. Any voltage will experience high current if resistance is too low. Current will be low if resistance is too high and voltage is okay. NOTE: Current increases as resistance decreases and decreases as resistance increases while the voltage remains constant, like in an automotive circuit.
Learn more about electrical appliances here :-
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