Answer:
11,890
Explanation:
First we need to know what is considered a significant figure.
A significant figure is a value that is not a zero at the start OR end of a value.
Which means, the 0 in the value of 90 or 0.363 are not considered a significant figure.
The 0 in the value of 3056 is considered a significant figure.
So from the table, we can deduce:
0.275 has 3 significant figures
750 has 2 significant figures
has 3 significant figures.
11,890 has 4 significant figures.
320,050 has 5 significant figures.
So from the above, we can already see the answer.
Any vector can be written as components along positive X and positive Y axes.
So vector A can be written as 
, where 
is the angle between vector A and positive X axis
So vector A = 
So components of vector B along X -axis =43.38 m/s
along Y-axis = 54.93 m/s
Answer:
5.2 m
Explanation:
from the question we are given the following
depth of pool (d) = 3.2 m
height of laser above the pool (h) = 1 m
point of entry of laser beam from edge of water (l) = 2.5 m
we first have to calculate the angle at which the laser beam enters the water (∝),
tan ∝ = \frac{1}{2.2}
∝ = 24.44 degrees
from the attached diagram, the angle with the normal (i) = 90 - 24.4 = 65.56 degrees
lets assume it is a red laser which has a refractive index of 1.331 in water, and with this we can find the angle of refraction (r) using the formula below
refractive index = \frac{sin i}{sin r}
1.331 = \frac{sin 65.56}{sin r}
r = 43.16 degrees
we can get the distance (x) from tan r = \frac{x}{3.2}
tan 43.16 = \frac{x}{3.2}
x = 3 m
To get the total distance we need to add the value of x to 2.2 m
total distance = 3 + 2.2 = 5.2 m
Answer:
3.78 m on the left side of the seesaw
Explanation:
The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:
(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r
Solve for r, and you get 3.78 on the left side.
Hope this helps!
Answer:
Explanation:
Angular acceleration is defined as the variation of angular speed with respect to time:
The relation between the angular speed and the linear speed is given by:
Replacing (2) in (1):
We need to convert 
to 
:
Recall that:
Replacing:
