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natita [175]
4 years ago
9

A typical loaded commercial jet airplane has an inertia of 2.1 × 105 kg (a) Which do you expect to require more energy: getting

the plane up to cruising speed or getting it up to cruising altitude? Will one be a lot more than the other or will they be comparable? (b) How much energy does it take to get the plane to a cruising speed of 270 m/s? (c) How much energy does it take to get the plane to a cruising altitude of 10.4 km? [Ignore dissipation.]
Physics
1 answer:
MrMuchimi4 years ago
6 0

Answer:

(a) It depends on what cruising speed and cruising altitude

(b) 7654.5 * 10^6 (J)

(c) 21425.04 * 10^6 (J)

Explanation:

Formula for Kinetic energy: E_k = \frac{mv^2}{2}

Formula for Potential energy E_p = mgh

(a) It actually depends on cruising speed and cruising altitude to tell which one requires more energy. However, cruising speed would have more impact than cruising altitude because it has a power of 2 in the energy formula.

(b) If we plug in v = 270 and m = 210000 to the Kinetic energy formula we should have

E_k = \frac{210000 * 270^2}{2} = 7654.5 * 10^6 (J)

(c) If we plug in h = 10.4 km = 10400 m, m = 210000 and g = 9.81 we should have

E_p = 210000 * 9.81 * 10400 = 21425.04 * 10^6 (J)

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A woman is standing in the ocean, and she notices that after a wave crest passes, five more crests pass in a time of 54.0 s. The
timama [110]

Answer:

a) f=0.1 Hz ; b) T=10s

c)λ= 36m

d)v=3.6m/s

e)amplitude, cannot be determined

Explanation:

Complete question is:

Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.

Given:

number of wave crests 'n'= 5

pass in a time't' 54.0s

distance between two successive crests 'd'= 36m

a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have

f=n/t

f= 5/ 54 => 0.1Hz

b)The time period of wave 'T' is the reciprocal of the frequency

therefore,

T=1/f

T=1/0.1

T=10 sec.

c)wavelength'λ' is the distance between two successive crests i.e 36m

Therefore, λ= 36m

d) speed of the wave 'v' can be determined by the product of frequency and wavelength

v= fλ => 0.1 x 36

v=3.6m/s

e) For amplitude, no data is given in this question. So, it cannot be determined.

5 0
3 years ago
Two thermometers are calibrated, one in de
zlopas [31]
-40 c = -40 f but k would be 233.15
6 0
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Alecsey [184]
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6 0
3 years ago
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On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3, length 88.8 cm and diameter 2.30 cm fro
vichka [17]

Answer:

w = 28.25 N

Explanation:

To do this, we need to use two expressions.

First, to calculate the weight of any object, we use the 2nd law of newton. In this case, the weight is:

w = m*g  (1)

However we do not have the mass of the rod. We need to calculate that. To calculate the mass, we'll use the expression of density which is:

d = m/V  

From here, we solve for mass:

m = d * V   (2)

Finally, we can know the volume of the rod, because is cylindrical, therefore, the volume of a cylinder is:

V = π * r² * h   (3)

So, in resume, we need to solve for the volume of the rod, then, the mass ans finally the weight. Let's calculate the volume of the rod, converting the units of centimeter to meters, just dividing by 100:

diameter = 2.3 cm ---> radius = 2.3/2 = 1.15 cm -----> 0.0115 m

Length or height = 88.8 cm ----> 0.888 m

Replacing in (3):

V = π * (0.0115)² * 0.888

V = 3.69x10⁻⁴ m

Now, let's use (2) to calculate the mass:

m = 7800 * 3.69x10⁻⁴

m = 2.88 kg

Finally for the weight, we'll use expression (1):

w = 2.88 * 9.81

<h2>w = 28.25 N</h2><h2>And this is the weight of the rod.</h2>
4 0
3 years ago
As you sit in a fishing boat, you noticed that 22 waves pass the boat every 60 seconds . If the distance from one crest to the n
Zinaida [17]

Answer:

0.1835m/s

Explanation:

The formula for calculating the speed of wave is expressed as;

v = fλ

f is the frequency - The number of oscillations completed in one seconds

If 22 waves pass the boat every 60 seconds,

number of wave that passes in 1 seconds = 22/60 = 0.367 waves

Therefore the frequency f of the wave is 0.367Hertz

λ (wavelength) is the distance between successive crest and trough of a wave

λ = 0.5m

Substitute the given values into the formula

v = fλ

v = 0.367 * 0.5

v = 0.1835

Hence the speed of the waves is 0.1835m/s

8 0
3 years ago
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