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natita [175]
3 years ago
9

A typical loaded commercial jet airplane has an inertia of 2.1 × 105 kg (a) Which do you expect to require more energy: getting

the plane up to cruising speed or getting it up to cruising altitude? Will one be a lot more than the other or will they be comparable? (b) How much energy does it take to get the plane to a cruising speed of 270 m/s? (c) How much energy does it take to get the plane to a cruising altitude of 10.4 km? [Ignore dissipation.]
Physics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

(a) It depends on what cruising speed and cruising altitude

(b) 7654.5 * 10^6 (J)

(c) 21425.04 * 10^6 (J)

Explanation:

Formula for Kinetic energy: E_k = \frac{mv^2}{2}

Formula for Potential energy E_p = mgh

(a) It actually depends on cruising speed and cruising altitude to tell which one requires more energy. However, cruising speed would have more impact than cruising altitude because it has a power of 2 in the energy formula.

(b) If we plug in v = 270 and m = 210000 to the Kinetic energy formula we should have

E_k = \frac{210000 * 270^2}{2} = 7654.5 * 10^6 (J)

(c) If we plug in h = 10.4 km = 10400 m, m = 210000 and g = 9.81 we should have

E_p = 210000 * 9.81 * 10400 = 21425.04 * 10^6 (J)

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Given:

The magnitude of each charge is q1 = q2 = 1 C

The distance between them is r = 1 m

To find the force when distance is doubled.

Explanation:

The new distance is

\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}

The force can be calculated by the formula

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On substituting the values, the force will be

\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}

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nydimaria [60]
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A 100 Kg man is diving off a 50 meter cliff. What is his kinetic energy when he is 20 meters from the water?
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Answer:

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From the question we are told that

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Generally the equation for Kinetic Energy is is mathematically given by

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K.E=29.403125J

8 0
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A brick is resting on a smooth wooden board that is at a 30° angle. What is one way to overcome the static friction that is hold
lubasha [3.4K]

Answer:

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Explanation:

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X axis

       fr - Wₓ = m    a                      (1)

Y axis  

       N- W_{y} = 0

       N = W_{y}

let's use trigonometry to find the components of the weight

        sin θ = Wₓ / W

        cos θ = W_{y} / W

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the friction force has the formula

         fr = μ N

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from equation 1

at the point where the force equals the maximum friction force

in this case the block is still still so a = 0

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We can see that the quantities in parentheses with constants, so as the angle increases, the applied force must be less.

This is the force that balances the friction force, any force slightly greater than F initiates the movement.

Consequently, to overcome the out of friction we must increase the angle of the plane

the correct answer is to increase the angle of the plane

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vova2212 [387]

Answer:

C. Each capacitor carries the same amount of charge.

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When two or more different capacitors are connected in series across a potential source, each capacitor carries the same amount of charge.

In a series connected capacitor, sane amount of charge flows through the capacitors while different potential difference is passed across them.

The capacitors have the same charge as the charge flowing out directly from the potential source called emf since the emf is the driving force of charge in a circuit.

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