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natita [175]
3 years ago
9

A typical loaded commercial jet airplane has an inertia of 2.1 × 105 kg (a) Which do you expect to require more energy: getting

the plane up to cruising speed or getting it up to cruising altitude? Will one be a lot more than the other or will they be comparable? (b) How much energy does it take to get the plane to a cruising speed of 270 m/s? (c) How much energy does it take to get the plane to a cruising altitude of 10.4 km? [Ignore dissipation.]
Physics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

(a) It depends on what cruising speed and cruising altitude

(b) 7654.5 * 10^6 (J)

(c) 21425.04 * 10^6 (J)

Explanation:

Formula for Kinetic energy: E_k = \frac{mv^2}{2}

Formula for Potential energy E_p = mgh

(a) It actually depends on cruising speed and cruising altitude to tell which one requires more energy. However, cruising speed would have more impact than cruising altitude because it has a power of 2 in the energy formula.

(b) If we plug in v = 270 and m = 210000 to the Kinetic energy formula we should have

E_k = \frac{210000 * 270^2}{2} = 7654.5 * 10^6 (J)

(c) If we plug in h = 10.4 km = 10400 m, m = 210000 and g = 9.81 we should have

E_p = 210000 * 9.81 * 10400 = 21425.04 * 10^6 (J)

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For each question, select the right answer from the choices below:
Leni [432]

Option (ii) B is the correct option. The object on the moon has greater mass.

To resolve this, utilize the formulas Force = Mass * Acceleration.

The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.

Calculating the mass on earth:

30 N = 9.8 m/s² * mass

This results in a mass of 3.0 kg for the object on Earth.

Calculating the mass of the moon:

30 N = 1.6 m/s²2 * mass

Thus, the moon's object has a mass of 19. kg.

This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).

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1 year ago
The diagram below shows the velocity vectors for two cars that are moving relative to each other.
scoundrel [369]

Answer:

The answer is "5 \ \frac{m}{s} \ west"

Explanation:

\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to  \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\

velocity of car | respect to car :

\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\

          =\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west

7 0
3 years ago
An object is launched with an initial speed of 30 m/s at an angle of 60° above the horizontal . What is the maximum height reach
matrenka [14]

Answer:

H = 34.43 m

Explanation:

Given that,

Initial speed of the object, u = 30 m/s

The angle of projection, \theta=60^{\circ}

We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.

H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(30)^2\times \sin^2(60)}{2\times 9.8}\\\\H=34.43\ m

So, the maximum height reached by the object is 34.43 m.

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3 years ago
State Ohms law in easy words
Alexus [3.1K]

Answer:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

7 0
3 years ago
Read 2 more answers
A small block of mass m1 = 0.4 kg is placed on a long slab of mass m2 = 2.8 kg. Initially, the slab is stationary and the block
mel-nik [20]

Answer:

v₁ = 0.375 m / s ,   x = 0.335 m

Explanation:

Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.

We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.

initial moment. Right at the start of the movement

       p₀ = m v₀ + 0

final moment. Just when it comes to equilibrium

      p_{f} = (m + M) v₁

how the forces are internal

       p₀ =p_{f}

       m v₀ = (m + M) v₁

       v₁ = m /m+M    v₀

let's calculate

       v₁ = 0.4 /(0.4 + 2.8)  3

       v₁ = 0.375 m / s

 

Let's apply Newton's second law to the Block, to find the friction force

Y axis

       N - W = 0

       N = W

       N = m g

where m is the mass of the block

the friction force has the formula

      fr = μ N

      fr = μ m g

We apply Newton's second law to slab    

X axis

       fr = M a

where M is the mass of the slab

       μ m g = M a

       a = μ g m / M

let's calculate

       a = 0.15  9.8  0.4 / 2.8

       a = 0.21 m / s²

With kinematics we can find the position

       v²= v₀²+2 a x

as the slab is initially at rest, its initial velocity is zero

       v² = 2 a x

       x = v2 / 2a

let's calculate

        x = 0.375²/2 0.21

        x = 0.335 m

4 0
3 years ago
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