All categories

3 years ago

Please help me answer this it is due by Sunday night.

Physics

1 answer:

Inessa05 [86]3 years ago

5 0

Answer:

Explanation:

You might be interested in

A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m

Mars2501 [29]

Answer:

formula used K=F/∆l

∆l is the elongation of the spring

F=10N
∆l=20mm===> 0.02m
K=10N divided 0.02m= 500N/m

6 0

3 years ago

What is electromagnet and list the types of electromagnet.

sineoko [7]

Answer:

radio waves, micro wave, x-rays

Explanation:

3 0

4 years ago

Read 2 more answers

A car travels along straight line for first half time with a speed of 40 km/h and the second half with a speed of 60km/h find th

Vesna [10]

Answer:

Average speed of car will be 48 km/hr

Explanation:

Let the total distance is 2d

It is given that first half of the distance car travels with a speed of 40 km/hr

So time taken to cover half of the distance $t_1=\frac{d}{40}hr$

Second half of the distance is covered with a 60 km/hr

So time taken to cover second half of the distance $t_2=\frac{d}{60}hr$

So total time to cover 2d distance $t=\frac{d}{60}+\frac{d}{40}=\frac{5d}{120}$

Average speed is the ratio of total distance to total time

So average speed $=\frac{2d}{\frac{5d}{120}}=48km/hr$

So average speed of car will be 48 km/hr

4 0

3 years ago

If you were to measure the number of liters of gas trapped in a bottle which of the following will you be describing

AnnyKZ [126]

B I'm pretty sure, took a test

5 0

3 years ago

Read 2 more answers

For small amplitudes of oscillation the motion of a pendulum is simple harmonic. Consider a pendulum with a period of 0.550 s Fi

Ivenika [448]

To solve this problem we will use the concepts related to the expression of energy for harmonic oscillator. From our given values we have that the period is equivalent to

$T = 0.55s$

Therefore the frequency will be the inverse of the period and would be given as

$f= \frac{1}{T}$

$f = \frac{1}{0.55}$

$f = 1.82s^{-1}$

The ground state energy of the pendulum is,

$E = \frac{1}{2} hv$

$E = \frac{1}{2}(6.626*10^{-34}J\cdot s)(1.82s^{-1})$

$E = 6.03*10^{-34}J$

The ground state energy in eV,

$E = 6.03 * 10^{-34}J(\frac{1eV}{1.6*10^{-19}J})$

$E = 3.8*10^{-15}eV$

The energy difference between adjacent energy levels,

$\Delta E = hv$

$\Delta E = (6.626*10^{-34}J\cdot s)(1.82s)$

$\Delta E = 12.1*10^{-34}J$

4 0

3 years ago