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lbvjy [14]
3 years ago
12

Alan travels 100 km in 5hrs. Find his average speed in km/h​

Physics
2 answers:
fgiga [73]3 years ago
5 0

Answer:

<h3>The answer is 20 km/hr</h3>

Explanation:

The average speed of an object given the time and distance covered can be found by using the formula

a =  \frac{d}{t}  \\

where

d is the distance

t is the time

From the question

d = 100 km

t = 5 hrs

We have

a =  \frac{100}{5}  \\

We have the final answer as

<h3>20 km/hr</h3>

Hope this helps you

Neporo4naja [7]3 years ago
3 0
25 km/h hope this helps
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A nucleus with a mass number of 64 has a mean radius of about: _________.
dangina [55]

Answer:

The correct option is A

Explanation:

From the question we are told that

The mass number is A= 64

Generally the mean radius is mathematically evaluated as

R  =  R_o A^{\frac{1}{3} }

Here R_o is a constant with a value  R_o =1.2*10^{-15}

So  

     R  =  1.2*10^{-15} *  64^{\frac{1}{3} }

      R  =   4.8 *10^{-15}

        R  =   4.8\ fm

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3 years ago
What keeps the particles of a liquid from spreading out to fill an entire container in the same way that gas particles do?
Sonbull [250]

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4 years ago
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A block of ice with mass 2.00 kg slides 0.750 m down an inclined plane that slopes downward at an angle of 36.9 degrees below th
zhannawk [14.2K]

Answer: V_{f}=2.96m/s    

Firstly we have to draw the Free Body Diagram (FBD) as shown in the figure attached.

Where the weight w of the block has an x-component and y-component:

w_{x}=wsin(\theta)    (1)

w_{y}=wcos(\theta)    (2)

As well as the Normal Force N:

N_{x}=Nsin(\theta)    (3)

N_{y}=Ncos(\theta)    (4)

In addition, we know N=w, then \sum F_{y}=0

In the X-component:

\sum F_{x}=m.a

m.a=w_{x}    (5)

Substituting (1) in (5):

wsin(\theta)=m.a    (6)

In addition, we know w=m.g, where m is the mass of the block and g the gravity acceleration, which is equal to 9.8m/{s}^{2}  

So:

m.g.sin(\theta)=m.a   (7)

a=g.sin(\theta)    (8)

a=5.88m/{s}^{2}    (9)   >>>>This is the acceleration of the block

On the other hand, we have the following equation that expresses a <u>relation between</u> the distance d with the acceleration a and time t:

d=\frac{1}{2}a{t}^{2}   (10)

We already know the value of  d and calculated a, we have to find t:

t=\sqrt{\frac{2d}{a}}   (11)

t=\sqrt{\frac{2(0.75m)}{5.88m/{s}^{2}}}   (12)

t=0.50s   (13) >>>This is the time it takes to the block to go from the initial velocity V_{o} to its final velocity V_{f}

If the acceleration is the variation of the velocity in time, we can use the following equation to find V_{f}:

V_{f}-V_{o}=a.t   (13)

If V_{o}=0

V_{f}=a.t   (14)

V_{f}=(5.88m/{s}^{2})(0.50s)   (15)

Finally we get the value of the Final Velocity of the block:

V_{f}=2.96m/s    

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