Question

A line has a slope of 3 and passes through the point (2,31). Write the equation of the line in slope-intercept form

Answer 1

Answer:

y=3x+25

Step-by-step explanation:

We are given a point and the slope, so let's use the slope-intercept equation.

$y-y_{1}=m(x-x_{1})$

where m is the slope and (x₁, y₁) is the point given. The slope is 3 and the point is (2,31). Therefore,

$m= 3 \\x_{1}=2\\y_{1}=31$

Substitute the values into the equation.

$y-31=3(x-2)$

We want the equation in slope intercept form: y=mx+b. We must isolate y on the left side of the equation.

First, distribute the 3. Multiply each term inside the parentheses by 3.

$y-31= (3*x)+(3*-2)$

$y-31=(3x)+(-6)$

$y-31=3x-6$

Next, add 31 to both sides of the equation.

$y-31+31=3x-6+31$

$y=3x-6+31$

$y=3x+25$

This equation is in slope intercept form, so our final answer is:

y= 3x+25 (slope⇒3 , y-intercept ⇒25)

Answer 2

Answer:

y=3x+25

Step-by-step explanation:

So to find the slope-intercept we need to find the slope and the y intercept. we already know the slope so to find the y intercept you subtract 2 from the x coordinate and 6 from the y, because the slope is 3. So the answer is y=3x+23