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storchak [24]
4 years ago
10

Which acid is almost completely ionized in a dilute solution at 298k?

Chemistry
1 answer:
Alex777 [14]4 years ago
5 0
Considering choices; 
a. CH3COOH
b. H2S
c. H2PO4
d. HNO3
The answer would be HNO3; this is because it the strongest acid. Strong acids are acids that are fully ionized while weak acids are only partially ionized. At the same concentrations, strong acids have a higher concentration of hydrogen than weak acids. Examples of strong acids include; hydrocloric acid and nitric acid, while weak acids include; ethanoic acids. 
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The standard Gibbs energy of reaction, ÄG°, for the dissociation of phenol is 56.4 kJ mol-1 at 298 K. Calculate the pKa of pheno
Neporo4naja [7]

Answer:

a.

9.88

Explanation:

ΔG = - 2.303 RT log Ka

ΔG is change in free energy at temperature T , Ka is equilibrium constant

- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa

- log Ka = 9.88 .

pKa = 9.88 .

4 0
3 years ago
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Nana76 [90]
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3 0
4 years ago
Categorize each hydrocarbon as being saturated or unsaturated.
Black_prince [1.1K]

As you have not provided the options, still we can figure out the answer by understanding the key difference between saturated and unsaturated hydrocarbons.

SATURATED HYDROCARBONS are those hydrocarbons which only consist of a carbon carbon single bonds. All the bonds are sigma there are no pi bonds at all. Examples are shown below.

While, UNSATURATED HYDROCARBONS are those hydrocarbons which may contain either a double bond or triple bonds or both of them between the carbon atoms as shown below.

6 0
3 years ago
What is the shape of the water molecule?
OlgaM077 [116]
I think the right one is b.
7 0
4 years ago
Read 2 more answers
A 34.0 gram sample of an un-known hydrocarbon is burned in excess oxygen to form 93.5 grams of carbon dioxide and 76.5 grams of
natka813 [3]

Answer:

The answer to your question is  CH₄

Explanation:

Process

1.- Write the possible chemical reaction

                   CxHy + O₂   ⇒    CO₂  +   H₂O

2.- Calculate the amount of carbon in the reaction

Molecular mass of CO₂ = 12 + 32 = 44 g

                         44 g of CO₂ ------------------- 12 g of carbon

                         93.5 g of CO₂ ----------------  x

                          x = (93.5 x 12) / 44

                          x = 25.5 g of carbon

3.- Calculate the mass of hydrogen in the sample

Molecular mass of water = 2 + 16 = 18 g

                         18 g of water -------------   2 g of hydrogen

                          76.5 g of water --------    x g of hydrogen

                           x = (76.5 x 2) / 18

                           x = 8.5 g of hydrogen

4.- Calculate the moles of carbon and hydrogen in the sample

                           12g of carbon ------------- 1 mol

                           25.5g of carbon ---------- x

                             x = (25.5 x 1) / 12

                              x = 2.12 moles of carbon

                            1 g of hydrogen ----------- 1 mol

                            8.5 g of hydrogen -------- x

                             x = (8.5 x 1) / 1

                             x = 8.5 moles of hydrogen

5.- Divide both number of moles by the lowest number

carbon = 2.12 / 2.12 = 1

hydrogen = 2.12 = 8,5 / 2.12 = 4

6.- Write the molecular formula

                                                    CH₄                                        

7 0
3 years ago
Read 2 more answers
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