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Vika [28.1K]
2 years ago
5

As a rock falls, some of its potential energy is transformed into kinetic energy. What is true about the mechanical energy durin

g this transformation?
A.
It decreases because potential energy is a kind of mechanical energy.
B.
It does not change because kinetic energy and potential energy are both kinds of mechanical energy.
C.
It increases because kinetic energy is a kind of mechanical energy.
D.
It does not change because kinetic energy and potential energy are not kinds of mechanical energy.
Chemistry
1 answer:
mars1129 [50]2 years ago
4 0

Answer:

a or b

Explanation:

because those are the most likely to be true

now it gives you two options so i thinks it might be B but you could choose A you got two options choose wisely

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What is the ratio of the areas of the signals in the h nmr spectrum of pentan-3-ol?
Damm [24]

The ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

<h3>What is a NMR spectrum?</h3>

Nuclear magnetic resonance spectroscopy is a spectroscopy that shows the detailed structure and chemical environment of a chemical element.

Pentan-3-ol contain 12 hydrogen atoms. In H-NMR spectra, hydrogen atoms have same environment gives a signal.

There are 4 different kinds of signals due of the 4 different environment experienced by these 12 hydrogens.

Thus, the  ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

Learn more about NMR spectrum

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8 0
2 years ago
Drag each tile to the correct image. Match each hydrocarbon class to its structure. carboxylic acid amine halocarbon alcohol
Sonja [21]

Answer:

1. Amine.

2. Alcohol.

3. Carboxylic Acid.

4. Halocarbon.

Explanation:

3 0
3 years ago
C2F4 effuses through a barrier at a rate of 4.6x10-6 mol/hour, while an unknown gas effuses at a rate of 5.8x10-6 mol/hour. What
umka21 [38]
The  molar mass  of  the unknown  compound  is   calculated   as   follows

let the unknown  gas be represented by   letter  Y

Rate of C2F4/  rate of  Y  = sqrt of   molar  mass of gas Y/ molar mass of  C2F4

 =  (4.6  x10^-6/ 5.8  x10^-6)  = sqrt  of  Y/ 100

remove  the  square  root  sign  by  squaring  in both  side

(4.6  x  10^-6 / 5.8  x10^-6)^2 =  Y/100

= 0.629 =Y/100

multiply  both side  by  100

Y=  62.9 is  the molar  mass of unknown  gas



5 0
3 years ago
Question 3 of 11
daser333 [38]

Answer:

c

Explanation:

b and d are out, the variables are changed. a would be a repetition, not a replication. c uses the same method and variables with a different control group

6 0
3 years ago
• 1) The pressure of a sample of gas in a 2.00-L container is 876 mmHg.
kifflom [539]

Answer:

4380 mmHg

Explanation:

Boyle's Law can be used to explain the relationship between pressure and volume of an ideal gas. The pressure is inversely related to volume, so if volume decrease the pressure will increase. It can be expressed in the equation as:

P1V1=P2V2

In this question, the first condition is 2L volume and 876 mmHg pressure. Then the system changed into the second condition where the volume is 400ml and the pressure is unknown. The pressure will be:

P1V1= P2V2

876 mmHg * 2L = P2 * 400ml /(1000ml/L)

P2= 876 mmHg * 2L / 0.4L

P2= 4380 mmHg

5 0
3 years ago
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