Atoms are the smallest particles of an element that can take part in a chemical reaction. During any chemical reaction no particles are created or destroyed: the atoms are simply rearranged from the reactants to the products. The products may have different properties to the reactants.
Mass is never lost or gained in chemical reactions. We say that mass is always conserved. In other words, the total mass of products at the end of the reaction is equal to the total mass of the reactants at the beginning.
This fact allows you to work out the mass of one substance in a reaction if the masses of the other substances are known.
Answer:
B) K2X
Explanation:
In an uncharged compound, the total oxidation state must be zero. The oxidation state of the calcium is +2, thus we get the following formula, where x is the oxidation state of the polyatomic ion X:
Also, it is known that potassium has an oxidation state of +1. Since the new compound also has a total oxidation state equal to zero, we get the following equation, where k is the number of K atoms:
That's how it is found that the compumd consists of 2 K+ ions and one X ion.
<span>284 g
First, lookup the atomic weights of all the elements involved.
Atomic weight of Calcium = 40.078
Atomic weight of Chlorine = 35.453
Now calculate the molar mass of CaCl2
40.078 + 2 * 35.453 = 110.984
Using that molar mass, calculate how many moles of CaCl2 you have.
445 g / 110.984 g/mol = 4.009586967 mol
Since each molecule of CaCl2 has 2 chlorine atoms, multiply the number of moles of CaCl2 by 2 to get the number of moles of Chlorine atoms.
4.009586967 * 2 = 8.019173935
And finally, multiply by the atomic weight of chlorine.
8.019173935 * 35.453 = 284.3037735
Since you have have 3 significant figures in your data, round the result to 3 significant figures, giving 284 grams.</span>
The first step is to use the formula from Boyle's Law.
[(351 L)(1.0 atm)]/(181L) = 1.94 atm.
To determine the depth of the location where the diver was working, 1.94 is multiplied by 10. Therefore, the location of the underwater archaeological site is 19.4 meters below the surface.
