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tatiyna
3 years ago
11

Which is greater 50 degree celcius or 50 degree fahrenheit?with solution plz.....​

Chemistry
1 answer:
zheka24 [161]3 years ago
4 0

Answer: 50 degrees Celsius is hotter than 50 degrees F. 50 degrees Celsius is half way between freezing and boiling

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Give reason nitrogen is a gas<br><br> Help:)
Mrrafil [7]
Nitrogen is a gas because it is an airlike fluid substance which expands freely to fill any space available, irrespective of it's quantity
7 0
4 years ago
Read 2 more answers
Why does the dilution equation, M 1 V 1 = M 2 V 2, work?
valentina_108 [34]

Answer:

d) The dilution equation works because the number of moles remains the same.

Explanation:

Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and <em>M</em>₁<em>V</em>₁ = 1 mol.

Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.

The volume has doubled, but the volume has halved, and <em>M</em>₂<em>V</em>₂ = 1 mol.

b) <em>Wrong</em>. The molar concentration changes on dilution.

c) <em>Wrong</em>. The volume changes on dilution.

a) <em>Wrong</em>, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula <em>M</em>₁<em>V</em>₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.

6 0
4 years ago
Read 2 more answers
When metallic sodium is dissolved in liquid sodium chloride, electrons are released into the liquid. These dissolved electrons a
qaws [65]

Answer:

The edge of the length is \mathbf{L = 8.54 \times 10^{-10} \ m}

Explanation:

From the given information:

The associated energy for a particle in three - dimensional box can be expressed as:

E_n = \dfrac{h^2}{8mL^2}(n_x^2+n_y^2+n_z^2)

here;

h = planck's constant = 6.626 \times 10^{-34} \ Js

n_i = the quantum no in a specified direction

m = mass (of particle)

L = length of the box

At the ground state n_x = n_y = n_z=1

The energy at the ground state can be calculated by using the formula:

E_1 =\dfrac{3h^2}{8mL^2}

At first excited energy level, one of the quantum values will be 2 and the others will be 1.

Thus, the first excited energy will be: 2,1,1

∴

E_2 =\dfrac{(2^2+1^2+1^2)h^2}{8mL^2}

E_2 =\dfrac{(4+1+1)h^2}{8mL^2}

E_2 =\dfrac{(6)h^2}{8mL^2}

The transition energy needed to move from the ground to the excited state is:

\Delta E= E_2 - E_1

\Delta E= \dfrac{6h^2}{8mL^2}-  \dfrac{3h^2}{8mL^2}

\Delta E= \dfrac{3h^2}{8mL^2}} ----- (1)

Recall that:

the  wavelength identified with the electronic transition is: 800 nm

800 nm = 8.0  × 10⁻⁷ m

However, the energy-related with the electronic transition is:

\Delta E =\dfrac{hc}{\lambda}

\Delta E =\dfrac{6.626 \times 10^{-34} \times 2.99 \times 10^8}{8.0 \times 10^{-7} }

\Delta E =2.48 \times 10^{-19}  \ J

Replacing the value of \Delta E in (1); then:

2.48 \times 10^{-19}= \dfrac{3h^2}{8mL^2}}

Making the edge length L the subject of the formula; we have:

L = \sqrt{\dfrac{3h^2}{8m \times2.48 \times 10^{-19}} }

L = \sqrt{\dfrac{3\times (6.626 \times 10^{-34})^2}{8(9.1 \times 10^{-31} ) \times2.48 \times 10^{-19}} }

\mathbf{L = 8.54 \times 10^{-10} \ m}

Thus, the edge of the length is \mathbf{L = 8.54 \times 10^{-10} \ m}

5 0
3 years ago
NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
Tanya [424]

Answer:

A = 0.023 m

Explanation:

The relation between the frequency of a radiation and its wavelength is given by the following expression.

where,

c is the speed of light (it has a constant value of 3.00 x 108 m/s)

A is the wavelength of the radiation v is the frequency of the radiation

In this case, the frequency is 13 GHz = 13 x

10° Hz = 13 x 1o° s-

The wavelength associated with this frequency is:

A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023

8 0
3 years ago
Distinguish(solid,liquid,gas)​
amm1812

Answer:

Explanation:

A solid, at a given temperature, has a definite volume  

and shape which may be affected by changes in  

temperature. Solids usually increase slightly in size  

when heated (expansion)  and usually  

decrease in size if cooled (contraction).A liquid, at a given temperature, has a  

fixed volume and will take up the shape of any  

container into which it is poured. Like a solid, a  

liquid’s volume is slightly affected by changes in  

temperature.

A gas, at a given temperature, has neither a definite  

shape nor a definite volume. It will take up the shape  

of any container into which it is placed and will  

spread out evenly within it. Unlike those of solids  

and liquids, the volumes of gases are affected quite  

markedly by changes in temperature.

8 0
3 years ago
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