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Rashid [163]
3 years ago
12

This particle is found in the nucleus and adds mass to the nucleus, but changing its number does not change what the element is.

This particle is the
A. proton.
B. photon.
C. neutron.
D. electron.
Physics
1 answer:
Sliva [168]3 years ago
5 0
Adding neutron to the nucleus creates new isotopes of that element. Mass of the nucleus will increase if you add neutron to it but element will remain the same. If you add proton to the nucleus, mass of the nucleus will change but also element will also change. That is, atom of the element will change. 

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Another word for stored energy is <br> 1 potential <br> 2 kinetic
scoray [572]

Answer:

Potential

Explanation:

Potential energy is the energy stored while kinetic energy is motional energy.

Potential itself means "having capacity/energy".

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
3 years ago
Physical science!!!!!!helpppp
ipn [44]

Answer:

Option B

10.36 m/s

Explanation:

Using the first given equation, then velocity=distance/time

Since distance is provided as 200 m and time, t is 19.3 seconds then substituting these figures yields

v=200/19.3=10.3626943

Rounding off to 2 decimal places, then

v=10.36 m/s

6 0
3 years ago
Liquid sodium can be used as a heat transfer fluid. Its vapor pressure is 40.0 torr at 633°C and 400.0 torr at 823°C. Calculate
kaheart [24]

Answer:

H vaporization = 100.0788 kJ/mol

Explanation:

Use clausius clapyron's adaptation for the calculation of Hvap as:

ln\frac {P_2}{P_1}=\frac {H_{vap}}{R}(\frac {1}{T_1}-\frac {1}{T_2})

Where,

P₂ and P₁ are the pressure at Temperature T₂ and T₁ respectively.

R is the gas constant.

T₂ = 823°C

T₁ = 633°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So, the temperature,

T₂ = (823 + 273.15) K = 1096.15 K

T₁ = (633 + 273.15) K = 906.15 K

P₂ = 400.0 torr , P₁ = 40.0 torr

R = 8.314 J/K.mol

Applying in the formula to calculate heat of vaporization as:

ln \frac {400}{40}=\frac {H_{vap}}{R} (\frac {1}{906.15}-\frac {1}{1096.15})

Solving for heat of vaporization, we get:

H vaporization = 100078.823 J/mol

Also, 1 J = 10⁻³ kJ

So,

<u>H vaporization = 100.0788 kJ/mol</u>

4 0
3 years ago
Help me guys pleasssseeee
pshichka [43]
B. Kinetic energy increases, potential energy decreases.
5 0
3 years ago
Sebutkan aplikasi gerak osilasi fisis
VLD [36.1K]

........................................................................................

6 0
3 years ago
Read 2 more answers
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