Answer:
2144 rad/s
Explanation:
R1 = R
ω1 = 536 rad/s
R2 = R/2
ω2 = ?
Mass is M
By use of angular momentum remains constant if no external force is acting on the body.
I1 ω1 = I2 ω2
The moment of inertia of solid sphere is 12/5 MR^2
So, 2/5 x M R^2 x 536 = 2/5 x M (R/2)^2 x ω2
536 = ω2 / 4
ω2 = 2144 rad/s
Answer:
R = 9.85 ohm , r = 0.85 ohm
Explanation:
Let the two resistances by r and R.
when they are connected in series:
V = 12 V
i = 1.12 A
The equivalent resistance when they are connected in series is
Rs = r + R
So, By using Ohm's law
V = i Rs
Rs = V / i = 12 / 1.12 = 10.7 ohm
R + r = 10.7 ohm .... (1)
When they are connected in parallel:
V = 12 V
i = 9.39 A
The equivalent resistance when they are connected in parallel

So, By using Ohm's law
V = i Rp
Rp = V / i = 12 / 9.39 = 1.28 ohm
.... (2)
by substituting the value of R + r from equation (1) in equation (2), we get
r R = 8.36 ..... (3)

..... (4)
By solvng equation (1) and (4), we get
R = 9.85 ohm , r = 0.85 ohm
Answer:
Pressure = ρgh
pressure (p) is measured in pascals (Pa)
density (ρ) is measured in kilograms per metre cubed (kg/m3)
The fore of gravitational field strength (g) is measured in N/kg or m/s 2
height of column (h) is measured in metres (m)
Answer = 235,200 Pa
Explanation:
Pressure = ρgh
Pressure = 1,000 x 9.8 x 24
Pressure = 235,200 Pa
Answer:
2.03 x 10²⁴N
Explanation:
Given parameters:
Mass of moon = 7.34 x 10²²kg
Mass of the earth = 5.97 x 10²⁴kg
Distance = 3.8 x 10⁵km
Unknown:
Gravitational force of attraction = ?
Solution:
To find the gravitational force of attraction between the masses, we use the expression below;
F =
G is the universal gravitation constant
m is the mass
1 and 2 represents moon and earth
r is the distance
F =
F =
= 2.03 x 10²⁴N