Problem 19.24a Using the reagents below, list in order (by letter, no period) those necessary to convert the starting material i
nto the given product: Note: More than 1 mole of the starting material may be used. Not all spaces provided may be needed. Type "na" in any space where you have no reagent. a. heat, -CO2 b. NaOEt c. (CH3CH2)2CuLi d. CH2Cl2, PCC e. C3H7C(O)CH(C2H5)C(O)C2H5 f. CH3CH2Li g. CH3C(O)Cl, AlCl3 h. NBS, ROOR i. H2NC(O)NH2 j. HN(CH3)2 k. OH-, H2O, heat then H3O l. H3O
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<u>Answer:</u> From the given gases, the greatest rate of effusion is of
<u>Explanation:</u>
Rate of effusion of a gas is determined by a law known as Graham's Law.
This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:
It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.
For the given gases:
Molar mass of
Molar mass of
Molar mass of
Molar mass of
Molar mass of
The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.
Hence, the greatest rate of effusion is of