The hydrosphere<span> includes water that is on the surface of the planet, underground, and in the air. A planet's </span>hydrosphere<span> can be liquid, vapor, or ice. On </span>Earth<span>, liquid water exists on the surface in the form of oceans, lakes, and rivers.</span>
Answer:
The answer to your question is 1544 g of CO₂
Explanation:
Data
mass of octane = 500 g
mass of CO₂ = ?
Balanced chemical reaction
2C₈H₁₈ + 25O₂ ⇒ 16CO₂ + 18H₂O
Process
1.- Calculate the molar mass of octane and of carbon dioxide
C₈H₁₈ = 2[(12 x 8) + (1 x 18)] = 2[(96 + 18] = 2[114] = 228 g
CO₂ = 16[(12 x 1) + (16 x 2)] = 16[12 + 32] = 16[44] = 704 g
2.- Calculate the mass of carbon dioxide produced
228 g of C₈H₁₈ ---------------- 704 g of CO₂
500 g of C₈H₁₈ --------------- x CO₂
x = (500 x 704) / 228
x = 352000/228
x = 1544 g of CO₂
A. Is fruit ripening dependent on the type of light the fruit is exposed to, because B, C, and D are all based on opinion and different mind sets whereas A can be found out through experimentation.
Answer:
Alkanes
Cycloalkanes
Ring flip
Lower
Angle
Equatorial
Axial
Explanation:
For alkanes, the general molecular formula is CnH2n+2 while for cycloalkanes, the general molecular formula is CnH2n.
The cycloalkanes could undergo a ring flip in which axial and equatorial hydrogen atoms are interconverted.
The lower energy conformation of alkanes is the anti conformation and not the gauche conformation due to steric strain.
When the bond angle in alkanes deviate from the ideal 109.5°, an angle strain has occurred.
For bulky groups, the equatorial position his preferred since it has more room than the axial position.
Answer:
1) The neutralization reaction will mot be completed.
2) pH = 0.6.
Explanation:
<em>1) Will the neutralization reaction be completed?</em>
For the neutralization reaction be completed; The no. of millimoles of the acid must be equal the no. of millimoles of the base.
The no. of millimoles of 125 mL of 2.0 M HCl = MV = (2.0 M)(125.0 mL) = 250.0 mmol.
The no. of millmoles of 175 mL of 1.0 M NaOH = MV = (1.0 M)(175.0 mL) = 175.0 mmol.
∴ HCl will be in excess.
∴ The neutralization reaction will mot be completed.
<em>2) If not what is the pH of the final solution?</em>
[H⁺] =[ (MV)HCl - (MV)NaOH]/V total = (250.0 mmol - 175.0 mmol) / (300.0 mL) = 0.25 M.
∵ pH = - log[H⁺]
<em>∴ pH =</em> - log(0.25) =<em> 0.6.</em>
