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SashulF [63]
3 years ago
14

WHEN PARKING NEAR A CORNER YOU MAY PARK YOUR VEHICLE NO CLOSER THAN HOW MAY FEET?

Mathematics
2 answers:
natta225 [31]3 years ago
3 0
You may park 20 feet from a crosswalk.


Temka [501]3 years ago
3 0
Where I live, you must be at least 19 feet from a crosswalk. It all depends on where you live, because the laws and rules differ. 
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How do you get the answer x=2.05, 2.05 from this equation?
nasty-shy [4]

x = cos (47) = Pi/3, cos 47 = X/3

Step-by-step explanation:

x = 2.05, 2.05 (2.05)²

8 0
3 years ago
Function f(x) = |x| is transformed to create function g(x) = |x - 7| + 2.What transformations are performed to function f to get
serg [7]

We will have the following:

*Function f is translated 7 units rigth.

*Function f is translated 2 units up.

6 0
1 year ago
The given line passes through the points (0, -3) and (2, 3).
puteri [66]

The equation, in point-slope form of the line that is  parallel to the given line and passes through the point  (-1, -1) is y + 1 = 3(x + 1).

<u>Solution:</u>

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and  passes through (-1, -1).

Now, let us find the slope of the given line.

\text { slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}, \text { where }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are points on that line }

\text { Then, } m=\frac{3-(-3)}{2-0}=\frac{3+3}{2}=\frac{6}{2}=3

So, slope of given line is 3,  

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right)} \\\\ {y-(-1)=3(x-(-1))} \\\\ {\rightarrow y+1=3(x+1)}\end{array}

Hence, the line equation is y + 1 = 3(x + 1).

6 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form
pogonyaev

Answer:

y = 3/5x+1

Step-by-step explanation:

y intercept - (0,1), so b=1

Slope = rise/run = 3/5, so m = 3/5

Our Answer is y = 3/5x+1

4 0
3 years ago
What is the root of 6x-48=0
enot [183]
Undistribute 6
(6)(x-8)=0
set to zero
x-8=0
add 8 to both sides
x=8
the root is at x=8
6 0
3 years ago
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