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4 years ago

WHEN PARKING NEAR A CORNER YOU MAY PARK YOUR VEHICLE NO CLOSER THAN HOW MAY FEET?

Mathematics

2 answers:

natta225 [31]4 years ago

3 0

You may park 20 feet from a crosswalk.

Temka [501]4 years ago

3 0

Where I live, you must be at least 19 feet from a crosswalk. It all depends on where you live, because the laws and rules differ.

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Michael, a freelance editor, charges the rates shown in the table below to edit manuscripts. The cost per page increases as the

timofeeve [1]

Using the equation, the cost per page Maria can afford is
25c -.05(25c) = 66.50
0.95*25*c = 66.50
c = 66.50/(0.95*25) = 2.80

The best quality of editing that Maria can afford is ...
Basic Proofreading

3 0

3 years ago

What is 162/3% of what number is 72

denpristay [2]

Answer:

x = 432

Step-by-step explanation:

72 / x = 16 2/3 / 100

7200= 16 2/3x

7200 / 16 2/3 = 432

16 2/3x / 16 2/3 = x

7 0

3 years ago

Need help, I cant simplify this

Kisachek [45]

Answer:

$7^{\frac{2}{5}}$

Step-by-step explanation:

Step 1: First apply radical rule in the given expression.

$\sqrt[n]{a}=a^{\frac{1}{n}}$

Here, $\sqrt[3]{7}=7^{\frac{1}{3}}, \sqrt[5]{7}=7^{\frac{1}{5}}$

The expression becomes $\frac{\sqrt[3]{7}}{\sqrt[5]{7}}=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}$

Step 2: Now, apply exponent rule in the above expression

$\frac{x^{m}}{x^{n}}=x^{m-n}$

So, the expression becomes, $7^{\left(\frac{1}{3}-\frac{1}{5}\right)}$ .

Step 3: Take cross multiply the denominator and numerator of the fraction in the power of 7.

$\Rightarrow 7^{\left(\frac{1}{3}-\frac{1}{5}\right)}=7^{\left(\frac{5-3}{15}\right)}=7^{\frac{2}{5}}$

The answer is $7^{\frac{2}{5}}$ .

Hence the simplified form of $\frac{\sqrt[3]{7}}{\sqrt[5]{7}}=7^{\frac{2}{5}}$ .

3 0

3 years ago

What is 82.4% written as a decimal? A. 8.24 B. 824 C. 82.4 D. 0.824

Fynjy0 [20]

Hey there!

In order to find the decimal we have to divide , the $percentage$ out of $100$

So, $\frac{82.4}{100} = 0.824$

$Answer: 0.824$ $(option D.)$

Good luck on your assignment and enjoy your day!

~ $MeIsKaitlyn:)$

7 0

4 years ago

What substance has a mass of 148g and a volume of 40cm3 ?

rusak2 [61]

The substance that has a mass of 148g and a volume of 40cm³ is 3.7g/cm³

In order to get the substance that has a mass of 148g and a volume of 40cm³, we need to first get the density of the substance.

Density is the ratio of mass per unit volume of a substance

Density = Mass/Volume

Given the following:

Mass = 148g

Volume = 40cm³

Density = 148/40

Density = 3.7g/cm³

Hence the density of the substance is 3.7g/cm³

Learn more here: brainly.com/question/17780219

6 0

2 years ago