Is D
Explanation : you have to divide the amounts too see how many cheese for one person and then you subtract them and you get you answer that will be like this
2.5 divided by 10 = 0.25
1.6 divided by 8 = 0.2
0.25 - 0.2 = 0.05
Step-by-step explanation:
I think you mean you want to find out 40% of a number,, when 60% of it is 180, so I'll answer that:
60% = 180
÷6
10% = 30
x4
40% = 120
(if you want to find 100%, multiply 30 by 10)
Hopefully this helps :)
Total distance covered by <span>George and Carmen
</span>x + y = 350
And they biked 80 kilometers more than they bussed
<span>80 + y = x </span>
Putting the value of x=80 + y in <span>x + y = 350:
</span>We get:
<span>80 + y + y = 350 </span>
<span>2y = 270 </span>
<span>y = 135 km</span>
<span>Substituting y = 135 in x + y = 350 </span>
<span>x + 135 = 350</span>
<span>x = 215 km </span>
Thus George and Carmen biked for 215 km and bussed for 135 km.
9514 1404 393
Answer:
Step-by-step explanation:
The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.
That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.
If k is subtracted, instead of added, then the point will be moved downward.
The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.
_____
<em>Comment on the question</em>
The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.
If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.
Answer:sorry for the delate
Step-by-step explanation: