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BlackZzzverrR [31]
4 years ago
7

A ball is thrown horizontally which factor will increase the flight time of the ball

Physics
1 answer:
Mariana [72]4 years ago
4 0
I think the answer to your question is wind and distance
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________ is the name for when a director decides where and when performers move and position themselves on the stage.
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Blocking/staging

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Which process requires the addition of energy to water?
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A hot air balloon is flying above Grovenburg. To the left side of the balloon, the balloonist measure the angle of depression to
Savatey [412]
Find enclosed file with a drawing and the calculations of all angles and all distances.

These are the results that you will find in it:

<span>Angle x = 90° - 22°15’  </span>

Angle y = 90° - 62°30'

Angle z = 22°15’ = 22.25°

Angle w = 62°30’ = 62.50°

 

tan(z) = H/a => a = H/tan(z)

tan(w) = H/b => b = H/tan(w)

 

a+b = 4 => H/tan(z) + H/tan(w) = 4 => H [1/tan(z) + 1/tan(x) ] = 4

 <span>   </span>H = 4 / {[1/tan(z) + 1/tan(x) ] } = 1.35 miles

<span>    </span>a = 1.35 / tan(22.25°) =  3.30 miles

<span>    </span>b = 4 – 3.30 = 0.7 miles

I hope it is very useful and you understand it. Let me know.




Download pdf
6 0
3 years ago
A ladder whose length L is 12 m and mass m is 45 kg rests against a wall. Its upper end is a distance h of 9.3 m above the groun
amm1812

Answer:

FN₁ = 1146.6N : Force exerted on the ladder by the floor , vertical and upward

FN₂ = 407.5 N : Force exerted on the ladder by the wall , horizontal and opposite to friction force between the floor and the ladder

Explanation:

The equilibrium equation are:

∑Fx=0

∑Fy=0

∑M = 0  

M = F*d  

Where:  

∑M : Algebraic sum of moments

M : moment  ( N*m)  

F : Force ( N)  

d :Perpendicular distance of the force to the point  ( meters )

Data

m =45 kg  : mass of the ladder

M =72 kg : mass of the fire fighter

g = 9.8 m/s²: acceleration due to gravity

L = 12 m : ladder length

h =  9.3 m: ladder height

L/3 = 12/3 = 4m Location of the center of mass of the ladder of the way up

L/2 = 12/2 = 6m Location of the center of mass of the  fire fighter

µ = 0 : coefficient of friction between the ladder and the wall

θ  : angle that makes  the  ladder  with the floor

sinθ = h/L = 9.3 m/12 m

θ =sin⁻¹( 9.3 / 12)

θ = 50.8°

Forces acting on the ladder

W₁ =m*g = 45 kg* 9.8 m/s² = 441 N: Weight of the ladder (vertical downward)

W₂ =M*g = 72 kg * 9.8 m/s² = 705.6 N : Weight of the fire fighter(vertical downward)  

FN₁ :Normal force that the floor exerts on the ladder (vertical upward)  (point A)

fs : friction force that the floor exerts on the ladder (horizontal and opposite the movement )(point A)  

FN₂ :  Normal Force that the wall exerts on the ladder ( horizontal and opposite to friction force between the floor and the ladder)

∑Fy=0

FN₁ -W₁ -W₂= 0

FN₁ = W₁ + W₂

FN₁ = 441N+ 705.6N

FN₁ = 1146.6N : Force exerted on the ladder by the wall (vertical and upward)

Calculation of the distances of the forces at the point A (contact point of the ladder on the floor)

d₁ = 4*cos 50.8° (m) = 2.53 m:  Distance from W₁ to the point A

d₂ =6*cos 50.8° (m)= 3.79 m  : Distance from W₂ to the point A

d₃ = 9.3 m : Distance from FN₂ to the point A

The equilibrium equation of the moments at the point A  (contact point of the ladder with the floor)  

∑MA = 0  

FN₂(d₃) - W₁( d₁) - W₂(d₂) = 0

FN₂(d₃) = W₁(d₁) + W₂(d₂)

FN₂(9.3) = (441 )(2.53) + (705.6)( 3.79 )

FN₂(9.3) = 1115.73 + 2674.2

FN₂ = (3790) / (9.3)  

FN₂ = 407.5 N : Force exerted on the ladder by the wall , horizontal and opposite to friction force between the floor and the ladder

8 0
4 years ago
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