Kinetic energy of the horse and rider = 1/2 (mass) (speed)²
At 4.0 m/s : KE = 1/2 (55kg) (4 m/s)² = 440 joules
At 6.0 m/s : KE = 1/2 (55kg) (6 m/s)² = 990 joules
She increased the kinetic energy of herself and her vehicle by 550 joules,
so she must have put at least that much work into it.
Answer:
P = 3.92 10¹⁰ W
Explanation:
The power is data by the expression
P = W / t
the work of a force is
W = F. y
the bold ones represent vectors. In this case the displacement is vertical upwards and the vertical forces upwards, therefore the angle is zero and the cos 0 = 1
W = F y
we substitute
P = F y / t
P = F v
as the body rises at constant speed the acceleration is zero and from the equilibrium condition
F -W = 0
F = mg
we substitute
P = m g v
let's calculate
P 1.00 10⁹ 9.8 4
P = 3.92 10¹⁰ W
Answer:
False
Explanation:
the inner planets have solid rocky dense surfaces
Answer:
a). a=0.2 
b). x=10m
c). v=2
Explanation:
Force forward push = 2000N
Resistive force due water=1800N
Net force=2000N-1800N
Fn=200N
m=1000kg
t=10sec
a).
b).
c).
In order to solve this problem it is necessary to apply the concepts related to intensity and specifically described in Malus's law.
Malus's law warns that
Where,
Angle between the analyzer axis and the polarization axis
Intensity of the light before passing through the polarizer
The intensity of the beam from the first polarizer is equal to the half of the initial intensity
Replacing with our the numerical values we get
Therefore the intensity of the light that emerges from the filter is 
