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guajiro [1.7K]
2 years ago
9

Which process requires the addition of energy to water?

Physics
1 answer:
Taya2010 [7]2 years ago
3 0

Water must absorb energy in order to melt, evaporate, or get warmer.

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A jet airliner moving initially at 406 mph (with respect to the ground) to the east moves into a region where the wind is blowin
astraxan [27]

Answer:

966 mph

Explanation:

Using as convention:

- East --> positive x-direction

- North --> Positive y-direction

The x- and y- components of the initial velocity of the jet can be written as

v_{1x} = 406 mph\\v_{1y} = 0

While the components of the velocity of the wind are

v_{2x} = (568)(cos 15^{\circ})=548.6 mph\\v_{2y} = (568)(sin 15^{\circ})=147.0 mph

So the components of the resultant velocity of the jet are

v_x = v_{1x}+v_{2x}=406+548.6=954.6 mph\\v_y = v_{1y}+v_{2y}=0+147.0=147.0 mph

And the new speed is the magnitude of the resultant velocity:

v=\sqrt{v_x^2+v_y^2}=\sqrt{(954.6)^2+(147.0)^2}=965.8 mph \sim 966 mph

6 0
3 years ago
A 300-n force acts on a 25-kg object. the acceleration of the object is?
Over [174]
To solve the answer use the equation: a = fnet / m

a = 300 N / 25 kg

300 N / 25 kg = 12m/s

The acceleration of the object is 12m/s

8 0
2 years ago
Read 2 more answers
PLZ HELP IM REALLY CONFUSED a boy is playing catch with his friend. He throws the ball straight up. When it leaves his hand, the
erastovalidia [21]

Answer:

K.E = 100 J

Final P.E = 100 J

Explanation:

The kinetic energy of any object can be given by the following formula:

K.E = (\frac{1}{2})mv^{2}

where,

K.E = Kinetic Energy

m = mass of ball = 2 kg

v = speed of ball

Initially, v = 10 m/s. Therefore, the initial K.E is given as:

K.E = (\frac{1}{2})(2\ kg)(10\ m/s)^{2}

<u>K.E = 100 J</u>

Now, at the highest point the K.E of the ball becomes zero. because the ball stops for a moment at the highest point and its velocity becomes zero. So, from Law of Conservation of energy:

Initial K.E + Initial P.E = Final K.E + Final P.E

Initial P.E is also zero due to zero height initially.

K.E + 0 = 0 + Final P.E

<u>Final P.E = 100 J</u>

3 0
3 years ago
Hazardous wastes are placed into categories to aid in _____.
torisob [31]
The waste that poses substantial or potential threats to public and environment health
Hazardous waste are actually defined as RCRA in 40 CFR 261 the the four hazardous traits are 
ignitability 
reactivity 
corrosivity  
toxicity 
i think its b
4 0
3 years ago
Read 2 more answers
A solid uniform cylinder of mass 4.1 kg and radius 0.057 m rolls without slipping at a speed of 0.79 m/s. What is the cylinder’s
Amiraneli [1.4K]

Answer:

The cylinder’s total kinetic energy is 1.918 J.

Explanation:

Given that,

Mass = 4.1 kg

Radius = 0.057 m

Speed = 0.79 m/s

We need to calculate the linear kinetic energy

Using formula of linear kinetic energy

K.E_{l}=\dfrac{1}{2}mv^2

K.E_{l}=\dfrac{1}{2}\times4.1\times(0.79)^2

K.E_{l}=1.279\ J

We need to calculate the rotational kinetic energy

K.E_{r}=\dfrac{1}{2}\times I\omega^2

K.E_{r}=\dfrac{1}{2}\times\dfrac{1}{2}\times mr^2\times(\dfrac{v}{r})^2

K.E_{r}=\dfrac{1}{4}\times m\times v^2

K.E_{r}=\dfrac{1}{4}\times4.1\times(0.79)^2

K.E_{r}=0.639\ J

The total kinetic energy is given by

K.E=K.E_{l}+K.E_{r}

K.E=1.279+0.639

K.E=1.918\ J

Hence, The cylinder’s total kinetic energy is 1.918 J.

8 0
3 years ago
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