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ladessa [460]
3 years ago
14

How to solve an equation using the completing the square?

Mathematics
1 answer:
djyliett [7]3 years ago
4 0
I usually used formula
f(x)=a(x+b/2a)^2+c-b/4

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Can you help me Its a test pls help
xxMikexx [17]
It’s just 9 LOL yeahhhhhhhhhhhhhggg hope it goes well lollll

4 0
3 years ago
Determine if the sequence is arithmetic. If it is, find the common difference. Is the sequence a function ?
BaLLatris [955]
6)\\r=a_{n+1}-a_n\to r=a_2-a_1=a_3-a_2=a_4-a_3=...\\\\a_1=-7;\ a_2=-10;\ a_3=-11;\ a_4=-13\\\\a_2-a_1=-10-(-7)=-10+7=-3\\a_3-a_2=-11-(-10)=-11+10=-1\\\\a_3-a_2\neq a_2-a_1\\\\\text{It's not an arithmetic sequence}


\r=\dfrac{a_{n+1}}{a_n}\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...\\\\8.)\\a_1=4;\ a_2=20;\ a_3=100;\ a_4=500\\\\r=\dfrac{20}{4}=\dfrac{100}{20}=\dfrac{500}{100}=5\\\\10.)\\a_1-30;\ a_2=-45;\ a_3=-50;\ a_4=-65\\\\\dfrac{a_2}{a_1}=\dfrac{-45}{-30}=\dfrac{3}{2}\\\\\dfrac{a_3}{a_2}=\dfrac{-50}{-45}=\dfrac{10}{9}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}
12.)\\a_1=-7;\ a_2=-14;\ a_3=-21;\ a_4=-28\\\\\dfrac{a_2}{a_1}=\dfrac{-14}{-7}=2\\\\\dfrac{a_3}{a_2}=\dfrac{-21}{-14}=\dfrac{3}{2}\\\\\dfrac{a_2}{a_1}\neq\dfrac{a_3}{a_2}\\\\\text{It's not a geometric sequence}\\\\\text{It's a function}


8 0
3 years ago
HELP WITH ONE MORE!!!!!!!!
Alexxx [7]

Answer:

f(x + 3) = (4x + 13)/(x - 3)

Step-by-step explanation:

If f(x) = (4x + 1)/(x - 6)

then in f(x + 3)...js replace x with (x + 3)...

f(x + 3) = (4(x + 3) + 1)/(x + 3 - 6)

;f(x + 3) = (4x + 13)/(x - 3)

3 0
3 years ago
If 5x-3y=12 and 4x-5y=17 what is the value of y?
il63 [147K]

Answer:

8y

Step-by-step explanation:


3 0
3 years ago
Pls help! Due today. The last box is the choices of a.m or p.m
butalik [34]

Answer: 12pm

Step-by-step explanation: it takes him 2 hours to fill 1800 another 2 hours would be 12pm if you have 1000+1000 you get 2000. then add 800 and 800. you get 1600 add them all together you get 3600.

4 0
3 years ago
Read 2 more answers
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