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Anton [14]
3 years ago
7

Which of the following would most likely utilize a particulate control device?

Physics
2 answers:
Alexandra [31]3 years ago
3 0

Answer:

d

Explanation:

Correct answer: D). All of the above The particulate control device is a device that is used for the separation of the material that is of a bigger size as compared to filter. In the factory smokestack, the particulate control device filters the particulate matter that is known to cause air pollution. In the vacuum cleaner, a fine dust particle is filtered out. In the laundry dryer, the water and dirt molecule is allowed to pass through it. Hence, all the options are correct.so therefore your answer would be all

Ierofanga [76]3 years ago
3 0

Answer: all of the above

Explanation:

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Wewaii [24]

Answer: 34

Explanation:

34

3 0
3 years ago
The manipulation of natural sounds via the medium of magnetic tape is called
alexandr1967 [171]
<span>The manipulation of natural sounds via the medium of magnetic tape is called "</span>Musique concrete".

Musique concrete refers to an experimental method of melodic composition utilizing recorded sounds as crude material. The strategy was created around 1948 by the French composer Pierre Schaeffer and his partners at the Studio d'Essai ("Experimental Studio") of the French radio framework. The major guideline of musique concrète lies in the collection of different regular sounds recorded on tape (or, initially, on plates) to deliver a montage of sound.
3 0
3 years ago
PLEASE HELP it takes tsooo long! lol ima fail! please help! thanks!
Natasha_Volkova [10]

Answer:

A and c, hope i helped xx

Explanation:

4 0
3 years ago
Read 2 more answers
Which of the following is a terrestrial habitat?<br>A) Pond B) Garden C) Lake D) River​
kenny6666 [7]

Answer:

garden

Explanation: All the other habitats are aquatic

8 0
3 years ago
How much equal charge should be placed on the earth and the moon so that the electrical repulsion balances the gravitational for
kumpel [21]

As we know that electrostatic force between two charges is given as

F = \frac{kq_1q_2}{r^2}

here we know that electrostatic repulsion force is balanced by the gravitational force between them

so here force of attraction due to gravitation is given as

F_g = 1.98 \times 10^{20} N

here we can assume that both will have equal charge of magnitude "q"

now we have

1.98 \times 10^{20} = \frac{kq^2}{r^2}

1.98 \times 10^{20} = \frac{(9\times 10^9)(q^2)}{(3.84 \times 10^8)^2}

1.98 \times 10^{20} = (6.10 \times 10^{-8}) q^2

now we have

q = 5.7 \times 10^{13} C

6 0
3 years ago
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