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2 years ago

7

Which of the following would most likely utilize a particulate control device?

2 answers:

Alexandra [31]2 years ago

3 0

Answer:

d

Explanation:

Correct answer: D). All of the above The particulate control device is a device that is used for the separation of the material that is of a bigger size as compared to filter. In the factory smokestack, the particulate control device filters the particulate matter that is known to cause air pollution. In the vacuum cleaner, a fine dust particle is filtered out. In the laundry dryer, the water and dirt molecule is allowed to pass through it. Hence, all the options are correct.so therefore your answer would be all

Ierofanga [76]2 years ago

3 0

Answer: all of the above

Explanation:

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Find the intensity of a 55 dB sound given I 0=10^-12W/m^2

MakcuM [25]

Answer:

3.16 × $10^{-7}$ W/ $m^{2}$

Explanation:

β(dB)=10 × $log_{10}(\frac{I}{I_{0} })$

$I_{0}$ = $10^{-12}$ W/ $m^{2}$

β=55 dB

Therefore plugging into the equation the values,

55=10 $log_{10}(\frac{I}{ [tex]10^{-12}$ })[/tex]

5.5= $log_{10}(\frac{I}{ [tex]10^{-12}$ })[/tex]

$10^{5.5}$ = $\frac{I}{10^{-12} }$

316227.76× $10^{-12}$ = I

I= 3.16 × $10^{-7}$ W/ $m^{2}$

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2 years ago

How long does it take a vehicle to reach a velocity of 32 m/s if it accelerates from rest at a rate of 4.2 m/s^2?

Marta_Voda [28]

Answer:

7.62

Explanation:

because you have to divide 32/4.2

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2 years ago

Planet Nine is speculated to be on average 20 times farther away from the Sun than Neptune (on average distance from the Sun). H

saveliy_v [14]

Answer:

The distance is 55.636 billion miles, or 528.2 AU.

Explanation:

Since the distance from the Sun to Neptune is 2.7818 billion miles, the distance from the Sun to Planet Nine would be 20 times that, which is:

$d=(20)(2781800000\ miles)=55636000000\ miles$

or 55.636 billion miles.

Since 1 astronomical unit (AU) is 93 million miles, that distance is also:

$d=(55636000000\ miles)(\frac{1AU}{93000000\ miles})=598.2\ AU$

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3 years ago

The temperature of a gas is increased by 10degree Celsius. what is the corresponding change on Fahrenheit scale?

Grace [21]

On a Fahrenheit thermometer, the gas becomes 18 degrees warmer.

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2 years ago

For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s? Recall that accel

Karo-lina-s [1.5K]

I think its half of pie so you divid that by 3.14 .

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2 years ago

Read 2 more answers