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zheka24 [161]
3 years ago
10

How many milligrams are equivalent to 150 dekagrams?

Physics
2 answers:
riadik2000 [5.3K]3 years ago
5 0
Hello,
150g=150×10000=15000000 dekg=1,5e^6dekg

Bye:-)
dybincka [34]3 years ago
4 0
 i believe  the answer is 1.5e+6

hope this helps!

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What is the potential difference (voltage) if the resistance of 20 ohms produces a current of 10 amperes?
JulijaS [17]

Answer:

200 volts

Explanation:

Ohm's Law: V = IR

I = 10 A

R = 20 ohms

V = (10)(20) = 200 volts

8 0
2 years ago
for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it​
Ilia_Sergeevich [38]

Answer:

O²⁻

Explanation:

Number of protons  = 8

Number of neutrons  = 9

Number of electrons  = 10

What type of atom or ion is it = ?

Solution:

Protons are the positively charged particle in an atom

Neutrons do not carry any charges

Electrons are negatively charged particles

 For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.

Now,

     Charge  = Number of protons  - Number of electrons

      Charge  =  8  - 10  = -2

The charge on the atom is -2 and so it is an oxygen ion with -2 charge

 The ion is O²⁻

8 0
2 years ago
According to newtons law of action reaction what is the most likely to occur if to ice skaters with approximately the same mass
Free_Kalibri [48]

Answer:

They would keep on moving but unless being acted upon or stop slowly because of the friction

Explanation:

7 0
3 years ago
In a Young's double-slit experiment, 610-nm-wavelength light is sent through the slits. The intensity at an angle of 2.95° from
Sliva [168]

Answer:

spacing between the slits is 405.32043 ×10^{-9}  m

Explanation:

Given data

wavelength = 610 nm

angle = 2.95°

central bright fringe = 85%

to find out

spacing between the slits

solution

we know that spacing between slit is

I = 4I_{0} × cos²∅/2

so

I/4I_{0}  = cos²∅/2

here I/4I_{0} is 85 % = 0.85

so

0.85 = cos²∅/2

cos∅/2 = √0.85

∅ = 2 ×cos^{-1} 0.921954

∅  = 45.56°

∅  = 45.56° ×π/180 = 0.7949 rad

and we know that here

∅  = 2π d sinθ / wavelength

so

d = ∅× wavelength /  ( 2π  sinθ )

put all value

d = 0.795 × 610×10^{-9} / ( 2π  sin2.95 )

d = 405.32043 ×10^{-9}  m

spacing between the slits is 405.32043 ×10^{-9}  m

7 0
3 years ago
A photon in a laboratory experiment has an energy of 5 eV. What is the frequency of this photon? (using the idea of the electron
andreyandreev [35.5K]
Answer and working shown on photo

7 0
3 years ago
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