Question

The volume of a gas at STP (standard temperature and pressure) is 5.34 L. What would the volume of the gas be at 1.54 atmospheres and 10.0 degrees C? (R = 0.0821 L·atm/mol·K ) *

Answer 1

Answer:

$V_2=3.59L$

Explanation:

Hello,

In this case, we can use the combined ideal gas law avoiding the usage of the universal ideal gas constant in order to understand the volume-pressure-temperature behavior at constant moles as given on the statement:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

Thus, since the temperature must be operated in absolute Kelvin units, we compute the required volume at 1.54 atm and 10.0 °C, considering that the initial STP conditions are 1 atm and 0 °C:

$V_2=\frac{1atm\times5.34L\times(10.0+273)}{1.54atm\times(0+273)K} \\\\V_2=3.59L$

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