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3 years ago

Can someone please help me solve this ASAP?

Mathematics

1 answer:

olganol [36]3 years ago

6 0

She has 5 quarters, and 3 nickels

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Would you measure the length of a jump rope in inches or in feet? explain your choice

yan [13]

Depending on the length of the jump rope but usually you may need both feet and inches. By checking the average lengths of a jump rope you have: 7ft, 8ft,9ft,10ft for different heights so from this information the correct answer is feet

5 0

3 years ago

Read 2 more answers

mrs.saledo wants to buy 1 1/2 quarts of whipping cream if whipping cream is sold in only 1 pint containers , how many containers

hram777 [196]

Answer:

She needs to buy 3 such containers.

Step-by-step explanation:

Mrs. Saledo wants to buy $1\frac{1}{2}$ quarts of whipping cream.

Now, $1\frac{1}{2}$ quarts = $\frac{3}{2}$ quarts = $\frac{3}{2} \times 2 = 3$ pints.

Since we know that 1 US liquid quart = 1 US liquid pints.

If the whipping cream is sold in only 1 - pint containers, then she needs to buy 3 such containers. ( Answer )

5 0

3 years ago

18 ÷ 6 × [4 - 3] + 6

shepuryov [24]

Answer:

Step-by-step explanation:

18 ÷ 6 × [1] + 6

18 ÷ 6 + 6

3 + 6

6 0

3 years ago

Read 2 more answers

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

4 years ago

Write an expression that shows how to multiply 4 times 362 using place value and expanded form

luda_lava [24]

$362=300+60+2\\\\4\times362=4\times(300+60+2)\\\\ues\ distributive\ property:\\\\4\times300+4\times60+4\times2=1200+240+8=\boxed{1448}$

3 0

3 years ago