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ziro4ka [17]
3 years ago
5

FOR 50 POINTS! -- Your car is parked at the high school. After school you take off and travel for 27 km towards Iowa City. At th

is point, you realize you forget your wallet and travel back to Tipton for 15 km before you find your wallet was just on the floor. You turn back and head towards Iowa city for 36 km.
What is your displacement?
Physics
2 answers:
Dovator [93]3 years ago
6 0

Answer:

36km

Explanation:

Im pretty sure displacment is the start and finish in a straight line

Vilka [71]3 years ago
4 0

Answer:

27-15= 12

Explanation:

The official displacement formula is as follows:

s = sf – si

s = displacement

si = initial position

sf = final position

I really hope this is right I felt really bad for getting it wrong last time and wanted to make it up to ya lol

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A weight trainer lifts a 90.0-kg barbell from a stand 0.90 m high and raises it to a height of 1.75 m. What is the increase in t
nirvana33 [79]

Answer:

∆PE = 749.7 J

At 0.9 m high, PE = 793.8 J

At 1.75 m high, PE = 1543.5 J

7 0
1 year ago
Two identical satellites orbit the earth in stable orbits. Onesatellite orbits with a speed vat a distance rfrom the center of t
Lelu [443]

Answer:

c) At a distance greater than r

Explanation:

If G= Gravitational constant

M= Mass of earth

r= distance from earth center

then orbital speed is ;

v = \sqrt{\frac{GM}{r} }

==> v²=GM/r

If speed of first satellite = V₁

==> V₁² = GM/r

==> r = GM/V₁²

If speed of second satellite say V₂ is less than V₁ then square of V₂ will be less than square of V₁ , and hence GM will be divided by less number in case of second satellite, and hence will give greater value of r as compared to first satellite.

So our answer is c

5 0
2 years ago
The near point of an eye is 48.5 cm. A corrective lens is to be used to allow this eye to focus clearly on objects at the distan
Masteriza [31]

Answer:

The focal length of the lens should be -51.5 cm (a concave lens).

Explanation:

The purpose of the lens is to make objects at 48.5 cm appear at the healthy near point. The healthy near point is 25.0 cm.

We use the lens formula

\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}

where <em>f</em> = focal length, <em>u</em> = object distance and <em>v</em> = image distance.

In this case, <em>u</em> = 48.5 cm and <em>v</em> = -25.0 cm.

<em>v</em> is negative because the image is virtual an not real. (Here, we are using the real-is-positive sign convention)

\dfrac{1}{f} = \dfrac{1}{48.5} + \dfrac{1}{-25.0} = -\dfrac{23.5}{1212.5}

f = -51.5

The negative sign indicates the lens is concave.

3 0
2 years ago
From 0 seconds to 4 seconds is the acceleration positive or negative?
Alenkinab [10]

Answer:

From 0 -4 seconds the acceleration is positive. (The graph is going upwards.)

From 6-10 seconds the acceleration is negative. (The graph is going downwards.)

7 0
3 years ago
Through which one of the following mediums is the velocity of a sound wave the greatest?
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<em><u>of an elastic material, the velocity of the wave is relatively</u></em>

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<em><u>5,060 meters per second. On the other hand, the velocity</u></em>

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6 0
2 years ago
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