Answer: C) The two particles will move away from each other
Explanation:
When two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies.
This is stated by Coulomb's Law:
"The electrostatic force
between two point charges
and
is proportional to the product of the charges and inversely proportional to the square of the distance
that separates them, and has the direction of the line that joins them"
Mathematically this law is written as:
Where
is a proportionality constant.
Now, if
and
have the same sign charge (both positive or both negative), a repulsive force will act on these charges.
Answer:
d = 10.2 m
Explanation:
When the car travels up the inclined plane, its kinetic energy will be used to do the work in climbing up. So according to the law of conservation of energy, we can write that:
![Kinetic\ Energy\ of\ the \ Car = Work\ Done\ while\ moving\ up\ the\ plane\\\frac{1}{2}mv^{2} = Fd](https://tex.z-dn.net/?f=Kinetic%5C%20Energy%5C%20of%5C%20the%20%5C%20Car%20%3D%20Work%5C%20Done%5C%20while%5C%20moving%5C%20up%5C%20the%5C%20plane%5C%5C%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D%20%3D%20Fd)
where,
m = mass of car
v = speed of car at the start of plane = (36 km/h)(1000 m/1 km)(1 h/3600 s)
v = 10 m/s
F = force on the car in direction of inclination = W Sin θ
W = weight of car = mg
θ = Angle of inclinition = 30°
d = distance covered up the ramp = ?
Therefore,
![\frac{1}{2}mv^{2} = mgdSin\theta\\\frac{1}{2}v^{2} = gdSin\theta\\\frac{1}{2}(10\ m/s)^{2} = d(9.81\ m/s^{2}) Sin\ 30^{0}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D%20%3D%20mgdSin%5Ctheta%5C%5C%5Cfrac%7B1%7D%7B2%7Dv%5E%7B2%7D%20%3D%20gdSin%5Ctheta%5C%5C%5Cfrac%7B1%7D%7B2%7D%2810%5C%20m%2Fs%29%5E%7B2%7D%20%3D%20d%289.81%5C%20m%2Fs%5E%7B2%7D%29%20Sin%5C%2030%5E%7B0%7D)
<u>d = 10.2 m</u>
Answer:
d = 1.954 Km
Explanation:
given,
total distance, D = 2.5 Km
in stretch A to B =
speed = 99 Km/h = 99 x 0.278 = 27.22 m/s time =t
in stretch B to C
time = 3.4 s
In stretch C to D
speed = 48 Km/h = 48 x 0.278 = 13.34 m/s time =t
we know,
distance = speed x time
distance of BC
using equation of motion
v = u + a t
27.22 = 13.34 - a x 3.4
a = 4.08 m/s²
uniform deceleration is equal to 4.08 m/s²
distance traveled in BC
![s = ut + \dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%20%3D%20ut%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
![s = 13.34\times 3.4 + \dfrac{1}{2}\times 4.08 \times 3.4^2](https://tex.z-dn.net/?f=s%20%3D%2013.34%5Ctimes%203.4%20%2B%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%204.08%20%5Ctimes%203.4%5E2)
s = 68.94 m
![3000 = 99 \times \dfrac{1000\ t}{3600}+ 68.94 + 48\times \dfrac{1000\ t}{3600}](https://tex.z-dn.net/?f=3000%20%3D%2099%20%5Ctimes%20%5Cdfrac%7B1000%5C%20t%7D%7B3600%7D%2B%2068.94%20%2B%2048%5Ctimes%20%5Cdfrac%7B1000%5C%20t%7D%7B3600%7D)
3000 = 27.5 t + 68.94 + 13.33 t
40.83 t = 2931.06
t = 71.79 s
distance travel in AB
distance = s x t
d = 27.22 x 71.79
d = 1954 m
d = 1.954 Km
distance between A and B is equal to 1.954 Km.
The magma cools very slowly so that the crystals of different minerals have time to grow. The magma molecules in have time to organize themselves into crystal formations before the magma hardens. The naked eye helps the Intrusive rocks that has large crystals be seen.
We are given
E = <span>2.64 × 10-21 J
h = </span><span>6.6 × 10-34 J s
The options given below are frequencies, therefore, the question must be asking about the frequency fo the given wave
The equation is
E = h f
Simply substitute and solve for f which is the frequency
f = </span>2.64 × 10-21 J / 6.6 × 10-34 J s
f = <span>4.00 × 1012<span> hertz</span></span>