All categories

2 years ago

An object blocks the path of a wave causing the wave to change direction is called what

Physics

2 answers:

lapo4ka [179]2 years ago

8 0

"Reflection" is the change direction of waves when blocked by obstacle

tresset_1 [31]2 years ago

7 0

The object is called "opaque" if it totally blocks causing the phenomenon of reflection to occur.

You might be interested in

Which countries produce the most greenhouse gas emissions?

Kipish [7]

india and china produce the most greenhouse gas emissions?

7 0

3 years ago

Does anyone know how to solve this?

kompoz [17]

Answer:

110 m

Explanation:

Draw a free body diagram of the car. The car has three forces acting on it: normal force up, weight down, and friction to the left.

Sum of the forces in the y direction:

∑F = ma

N − mg = 0

N = mg

Sum of the forces in the x direction:

∑F = ma

-F = ma

-Nμ = ma

Substitute:

-mgμ = ma

-gμ = a

Given μ = 0.40:

a = -(9.8 m/s²) (0.40)

a = -3.92 m/s²

Given that v₀ = 30 m/s and v = 0 m/s:

v² = v₀² + 2aΔx

(0 m/s)² = (30 m/s)² + 2 (-3.9s m/s²) Δx

Δx ≈ 110 m

8 0

2 years ago

Read 2 more answers

Hi, so i have to find T1, can some1 help?

iragen [17]

30.1 N

Explanation:

Given:

$W_1 = 16\:\text{N}$

$W_2 = 8\:\text{N}$

Let's write the components of the net forces at the intersections. Note that the system is equilibrium so all the net forces are zero.

Forces involving W1:

$x:\:\:\:-T_1 + T_3\cos \alpha = 0\:\: \\ \text{or}\:\:T_2 = T_3\cos \alpha\:\:\:\:\:(1)$

$y:\:\:\:T_3\sin \alpha - W_1 = 0\:\:\: \\ \text{or}\:\:\:T_3\sin \alpha = W_1\:\:\:\:\:\:(2)$

Forces involving W2:

$x:\:\:\:T_1\sin 53 - T_3\sin \alpha = W_2\:\:\:\:\:\:\:(3)$

$y:\:\:\:T_4 - T_1\cos 53 - T_3\cos \alpha = 0\:\:\:\;(4)$

Substitute (2) into (3) and we get

$T_1\sin 53 - W_1 = W_2$

Solving for $T_1$ ,

$T_1 = \dfrac{W_1 + W_2}{\sin 53} = 30.1\:\text{N}$

7 0

2 years ago

3.113 A heat pump is under consideration for heating a research station located on Antarctica ice shelf. The interior of the sta

Lyrx [107]

Answer:

a. β = 8.23 K

b. β = 28.815 K

Explanation:

Heat pump can be find using the equation

β = TH / TH - TC

TH = 15 ° C + 273.15 K = 288.15 K

TC = - 20 ° C + 273.15 K = 253.15 K

β = 288.15 K / 288.15 k - ( 253.15 K )

β = 8.23 K

TH = 15 ° C + 273.15 K = 288.15 K

TC = 5 ° C + 273.15 K = 278.15 K

β = 288.15 K / 288.15 k - ( 278.15 K )

β = 28.815 K

6 0

2 years ago

An object moves in one dimension according to the function x(t)=13at3, where a is a positive constant with units of ms3. During

9966 [12]

Answer:

B) 1/5 ba^2 T^5

Explanation:

The dissipated energy is given by the work done over the object by the force F=-bv. The work is given by the following formula:

$dW=Fdx$

you derivative the function f(x) and replace v by the derivative dx/dt you obtain:

$v=\frac{dx}{dt}=at^2\\\\dx=at^2dt\\\\W=\int_0^{T} Fdx=-\int_0^Tvbdx=-\int_0^Tb(at^2)(at^2dt)\\\\W=-ba^2\frac{T^5}{5}=-\frac{1}{5}ba^2T^5$

hence, the dissipated energy is 1/5 ba^2 T^5

7 0

2 years ago