Answer:
The current is halved
Explanation:
The relationship between the current and the resistance is given by Ohm's Law, as follows:

where,
V = Voltage
I = Current
R = Resistance
Therefore, if we double the resistance:

Hence the correct option is:
<u>The current is halved</u>
F = ma, where m = mass in kg, a = acceleration in m/s², F = Force in Newton
F = 1 * 2
F = 2 N
Force needed is 2 Newtons.
Answer:
<em><u>a) </u></em><em><u> </u></em><em><u>Carbonic acid</u></em>
<em><u>b</u></em><em><u>)</u></em><em><u> </u></em><em><u>ammonium hydroxide</u></em>
<em><u>c</u></em><em><u>)</u></em><em><u> </u></em><em><u>Aluminum phosphate</u></em>
<em><u>d</u></em><em><u>)</u></em><em><u> </u></em><em><u>Sodium hydroxide</u></em>
<em><u>e</u></em><em><u>)</u></em><em><u> </u></em><em><u>Gold trichloride</u></em>
Explanation:
<em>I</em><em> </em><em>hope this</em><em> </em><em>will help</em><em> </em><em>you</em><em> </em><em>buddy</em><em> </em>
R = 0.407Ω.
The resistance R of a particular conductor is related to the resistivity ρ of the material by the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of the material.
To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.
We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4. Then:
R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]
R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²
R = 0.407Ω
Answer:
Is there a map of the town? It doesn't make sense without coridnates or street lengths. If it was a straight isosilese triangles the return time is 3:36pm. This answer doesn't make sense if there is a map.
Explanation:
Side a is 12km Side b 15 km Side c 19.21 km.
9am depearture
11am 12km away rest
11:30am starts at 10 km/h
1:00 pm reaches town
2:00pm done lunch
3:36 pm return home.