Under which conditions do both convex and concave mirrors form virtual images? State whether or not each can form a real image.
If the mirror can form a real image, describe how this works.
1 answer:
Hi!
Convex mirrors always form virtual images regardless of object position and the image is formed behind the mirror in both cases I.e. at infinity and between infinity and the pole. The image is diminished in both the cases.
Concave mirrors form a virtual image when the object is placed in between the Principal focus and the Pole and the image is formed behind the mirror. The virtual image is enlarged in this case. In all other object positions I.e. at infinity, beyond Center of curvature, at Center,between centre of curvature and principal focus and at principal focus, a real and an inverted image of the object is formed.
The ray diagrams for all the positions for the object in concave and convex mirrors are given below:
Convex mirrors always form virtual images regardless of object position and the image is formed behind the mirror in both cases I.e. at infinity and between infinity and the pole. The image is diminished in both the cases.
Concave mirrors form a virtual image when the object is placed in between the Principal focus and the Pole and the image is formed behind the mirror. The virtual image is enlarged in this case. In all other object positions I.e. at infinity, beyond Center of curvature, at Center,between centre of curvature and principal focus and at principal focus, a real and an inverted image of the object is formed.
The ray diagrams for all the positions for the object in concave and convex mirrors are given below:
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Answer:
A) 1568.60 Hz
B) 1437.15 Hz
Explanation:
This change is frequency happens due to doppler effect
The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source
where
C = the propagation speed of waves in the medium;
Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;
Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.
A) Here the Source is moving towards the receiver(C-Vs)
and the receiver is standing still (Vr=0) therefore the observed frequency should get higher
B)Here the Source is moving away the receiver(C+Vs)
and the receiver is still not moving (Vr=0) therefore the observed frequency should be lesser