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Novosadov [1.4K]
3 years ago
14

Under which conditions do both convex and concave mirrors form virtual images? State whether or not each can form a real image.

If the mirror can form a real image, describe how this works.

Physics
1 answer:
-Dominant- [34]3 years ago
3 0
Hi!

Convex mirrors always form virtual images regardless of object position and the image is formed behind the mirror in both cases I.e. at infinity and between infinity and the pole. The image is diminished in both the cases.

Concave mirrors form a virtual image when the object is placed in between the Principal focus and the Pole and the image is formed behind the mirror. The virtual image is enlarged in this case. In all other object positions I.e. at infinity, beyond Center of curvature, at Center,between centre of curvature and principal focus and at principal focus, a real and an inverted image of the object is formed.
The ray diagrams for all the positions for the object in concave and convex mirrors are given below:

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Answer: The molar heat capacity of aluminum is 25.3J/mol^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of water = 130.0 g

m_2 = mass of aluminiunm = 23.5 g

T_{final} = final temperature = 26.0^oC=(273+26)K=299K

T_1 = temperature of water = 23^oC=(273+23)K=296K

T_2 = temperature of aluminium = 100^oC=273+100=373K

c_1 = specific heat of water= 4.184J/g^0C

c_2 = specific heat of aluminium= ?

Now put all the given values in equation (1), we get

130.0\times 4.184\times (299-296)=-[23.5\times c_2\times (299-373)]

c_2=0.938J/g^0C

Molar mass of Aluminium = 27 g/mol

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The object's speed will remain constant after the it leaves his hand.

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Answer:

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Opposite direction: t=27.53s; d=0.73Km

Explanation:

If the automobile and the train are traveling in the same direction, then the automobile speed relative to the train will be v_{AT}=v_A-v_T (<em>the train must see the car advancing at a lower speed</em>), where v_A is the speed of the automobile and v_T the speed of the train.

So we have v_{AT}=(95km/h)-(75Km/h)=20Km/h.

So the train (<em>anyone in fact</em>) will watch the automobile trying to cover the lenght of the train L at that relative speed. The time required to do this will be:

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