Under which conditions do both convex and concave mirrors form virtual images? State whether or not each can form a real image.
If the mirror can form a real image, describe how this works.
1 answer:
Hi!
Convex mirrors always form virtual images regardless of object position and the image is formed behind the mirror in both cases I.e. at infinity and between infinity and the pole. The image is diminished in both the cases.
Concave mirrors form a virtual image when the object is placed in between the Principal focus and the Pole and the image is formed behind the mirror. The virtual image is enlarged in this case. In all other object positions I.e. at infinity, beyond Center of curvature, at Center,between centre of curvature and principal focus and at principal focus, a real and an inverted image of the object is formed.
The ray diagrams for all the positions for the object in concave and convex mirrors are given below:
Convex mirrors always form virtual images regardless of object position and the image is formed behind the mirror in both cases I.e. at infinity and between infinity and the pole. The image is diminished in both the cases.
Concave mirrors form a virtual image when the object is placed in between the Principal focus and the Pole and the image is formed behind the mirror. The virtual image is enlarged in this case. In all other object positions I.e. at infinity, beyond Center of curvature, at Center,between centre of curvature and principal focus and at principal focus, a real and an inverted image of the object is formed.
The ray diagrams for all the positions for the object in concave and convex mirrors are given below:
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Answer:
W = 3.12 J
Explanation:
Given the volume is 1.50*10^-3 m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:
β = 69*10^-6 (°C)^-1 V = 1.50*10^-3 m^3 ΔT = 298°C
So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):
So ΔV = 3.0843*10^-5 m^3
Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa
To get work, multiply the air pressure and the volume change.
W = 3.12 J
Hope this helps!
Answer:
Part a)
Part b)
North of East
Explanation:
Speed of train towards East = 60 km/h
displacement towards East is given as
now it turns towards 50 degree East of North
so its distance is given as
then finally it moves towards west for 50 min
Now the total displacement of the train is given as
now total time duration of the motion is given as
now average velocity is given as
Part a)
magnitude of the average velocity is given as
Part b)
Direction of the velocity is given as
North of East