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const2013 [10]
4 years ago
8

A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the

bat with a speed of 25 meters per second. What is the magnitude of the average force exerted by the ball on the bat
Physics
1 answer:
Furkat [3]4 years ago
8 0

Answer:

75 Newtons.

Explanation:

From Newton's second law of motion,

F = m(v-u)/t................... Equation 1

Where F = force exerted by the ball on the bat, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball, t = time

Given: m = 0.6 kilogram, u = 0 meter per seconds (at rest), v = 25 meters per seconds, t = 0.2 seconds.

Substitute into equation 1

F = 0.6(25-0)/0.2

F = 3(25)

F = 75 Newton.

Hence the magnitude of the average force exerted by the ball on the bat = 75 Newtons.

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<h3>What is Buoyancy?</h3>

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All material submerged in a liquid under the action of buoyancy, for this reason we have that the value on the scale will be increased with a system of a wood floating in water.

See more about Buoyancy at brainly.com/question/19168433

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5 0
2 years ago
A painter sits on a scaffold that is connected to a rope passing over a pulley. The other end of the rope rests in the hands of
Doss [256]

Solution :

a). From Newtons second law,

F = ma

The total tension force is 2T.

∴ 2T - (m + M)g = (m+ M)a

Then

$a=\frac{2T-(m+M)g}{m+M}$

$a=\frac{2\times 600-(52+63)9.8}{52+63}$

   $=0.63 \ m/s^2$

b). From the person,

   F = ma

 T - Mg + N = Ma

or N = Ma + Mg - T

        = (63 x 9.8) + (52 x 9.8) - 600

        = 617.4 + 509.6 - 600

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3 years ago
A 70 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m . What is the effective spring
ANEK [815]

Answer:

29856.521 N/m

Explanation:

m=Mass\ of\ diver=70\ kg\\x=Length\ compressed\ by\ spring=2.3\times 10^{-2}\ m\\a=Acceleration\ due\ to\ gravity=9.81\ m/s^2\\F=Force\ exerted\ by\ diver=m\times a\\\Rightarrow F=70\times 9.81\\\Rightarrow F=686.7\ N\\k=spring\ constant\\F=k\times x\\\Rightarrow k=\frac {F}{x}\\\Rightarrow k=\frac {686.7}{2.3\times 10^{-2}}\\\therefore k=29856.521\ N/m

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4 years ago
How is capacitance related to the distance between the plates of a capacitor?
svetlana [45]

Answer:C

Explanation: I studied, and C is correct

5 0
3 years ago
although the pivot exerts a force on the ruler it does not exert a torque with respect to the pivot point. why not?
allsm [11]

Answer:

The situation is not shown, however if one calculates torques about the pivot point, then the pivot point itself exerts no torque because the force applied by the pivot point exerts zero torque because Fp * L = 0 where L = 0 in this case.

If one wants to calculate torques about, say, the end of the ruler then one would need to calculate the torque applied by the pivot point.

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