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3 years ago

A sample of bromine gas at 79.06 kPa experiences a change in volume from 63.299 L to 69.057 L.

Physics

1 answer:

AlladinOne [14]3 years ago

3 0

Answer:

74.47 kPa

Explanation:

As provided in the question, Boyle's law follows that

Pressure 1 x volume 1=pressure 2 x volume 2

Given that

Pressure 1 =79.06 kPa

volume 1=63.299L

pressure 2=unknown

Volume 2=69.057L

Substituting these into the formula then

79.06*63.299=69.057*P2

Making pressure 2 the subject of the formula

$P_2=\frac {79.06*63.299}{69.057}=72.467945899763\\P_2\approx 74.47kPa$

Therefore, the resulting pressure, rounded off to two decimal places is approximately 74.47 kPa

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