Answer:
Step-by-step explanation:
Dimensions of the backyard is 14 m by 15 m
<u>The length of the fence is the perimeter of the backyard.</u>
- P = 2(l +w)
- P = 2(15 + 14) = 2(29) = 58 m
One meter of the fence costs $6.63
<u>Cost of the entire fence is:</u>
Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way
Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
=-180
find the sum =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.
so (n-3)(n+60)
divide by a in this case it 18
so (n<u>-3</u>)(n+<u>60</u>)
18 18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u> 18 10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"
=(18n-3)(10n-3)
therefore your answer is (18n-3)(10n-3)
I hoped this helped :)
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
I think the answer is D
Hope it helps
So to get the sides you need to cube them
(192)^1/3---->5.769
(375)^1/3---->7.21125
7.21125-5.769= 1.44225
3^(1/3)= 1.44225
Answer: A
