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3 years ago

H2 + N2 ---> NH3

Chemistry

1 answer:

Stolb23 [73]3 years ago

4 0

The balanced equation would be
3H2 + N2 ———> 2NH3

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the men's world record for swimming 1500.0 m in a long course pool (as of 2007) is 14 min 34.56 s. At this rate, how many second

Lyrx [107]

140 s. It would take 140 s to swim 0.150 mi .

Step 1. Convert the time to seconds

Time = 14 min × (60 s/1 min) + 34.56 s = 840 s + 34.56 s = 874.56 s

Step 2. Convert miles to metres

Distance = 0.150 mi × (1609.3 m/1 mi) = 241.4 m

Step 3. Calculate the time to swim 241.4 m

Time = 241.4 m × (874.56 s/1500 m) = 140 s

(As of 2012, the men’s freestyle record for 1500 m was 14:31.02.)

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3 years ago

Look at the periodic table. Find the element carbon. What is its symbol?

Sliva [168]

A. ca is the answer because its short for carbon

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3 years ago

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Fe3+(aq) (yellow) + SCN-(aq) (colorless) FeSCN2+(aq) (blood-red) Chloride ions are colorless. Potassium ions are also colorless.

harina [27]

Explanation:

$Fe^{3+}\text{(aq)(yellow)}+SCN^-\text{(aq)(colorless)}\rightleftharpoons FeSCN^{2+}\text{(aq)(blood-red)}$

$K^+\text{(aq)(colorless)}+Cl^-\text{(aq)(colorless)}\rightarrow KCl$

The above two reactions xcan also be written in form of single chemcial equation:

$FeCl_3+K(SCN)\rightleftharpoons KCl+[Fe(SCN)]Cl_2(blood-red)$

1. Color of ferric chloride solution is yellow. This is due to presence of ferric ions which have yellow color in their aqueous solutions.

2. KSCN has the colorless solution. This due to potassium ion forms colorless aqueous solution.

3. On mixing, KSCN with $FeCl_3$ we will get blood red color solution of $[FeSCN]Cl_2$ .

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3 years ago

How many grams of MgCl2 would be needed to make 5.3 liters of a 0.25 molar solution? Round your answer to the nearest 0.01,

GuDViN [60]

Answer: 126.1 grams of are needed to make 5.3 L of 0.25 M solution

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

To calculate the mass of solute for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{given mass of solute}}{\text {Molar mass of solute}\times \text{Volume of solution in L}}$

$0.25M=\frac{x}{95.2g/mol\times 5.3L}$

$x=126.1g$

Thus 126.1 grams of are needed to make 5.3 L of 0.25 M solution

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2 years ago

Can you help me find the role for each organism

Rainbow [258]

The first one is Producer and second level consumer
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the third one is: carnivore and second level consumer
the fourth one is: herbivore and first level consumer

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3 years ago