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netineya [11]
2 years ago
9

Lead has an atomic number of 82. Which statement describes all neutral atoms and ions of lead?

Chemistry
1 answer:
IRINA_888 [86]2 years ago
6 0

The neutral atom of lead must have 82 protons while ions can have b or less than 82.

The atomic number of an element is the number of protons in the nucleus of the element.

Also, for neutral atoms, the number of protons equals the number of electrons.

In ionic form, the number of protons/electrons of an atom may vary and be different from that of the neutral form.

Positive charges mean that the ion has less proton than its neutral version while negative charges mean that it has more electrons than its neutral version.

Thus, the neutral atom of lead will contain an equal number of protons as the electrons while its ionic form can have more or less than 82 protons.

More on atoms can be found here: brainly.com/question/803445?referrer=searchResults

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Metric prefixes 9th grade level
zhannawk [14.2K]

Answer:

<h3>A metric prefix is a unit prefix that precedes a basic unit of measure to indicate a multiple or submultiple of the unit. All metric prefixes used today are decadic. Each prefix has a unique symbol that is prepended to any unit symbol.</h3>

6 0
3 years ago
An object has a velocity of 8m/s and a kinetic energy of 480 j what is the mass of the object
MariettaO [177]
Kinetic energy=Ek
Ek=(1/2)mv²
Ek=480 J
v=8 m/s
mass=?

Ek=(1/2)mv²
480 J=(1/2)m(8 m/s)²
480 J=(32 m²/s²) m
m=(480 J)/(32 m²/s²)=15 kg

answer: the mass of the object is 15 kilograms. 
3 0
3 years ago
When a chemical reaction is run in aqueous solution inside a calorimeter, the temperature change of the water (and Ccal) can be
Yakvenalex [24]

Answer:

The total change in enthalpy for the reaction is - 81533.6 J/mol

Explanation:

Given the data in the question;

Reaction;

HCl + NaOH → NaCl + H₂O

Where initial temperature is 21.2 °C and final temperature is 28.0 °C. Ccal is 1234.28 J

Moles of NaOH  = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol

Moles of HCl = 50.mL × 1.00 M = 50.0 mmol = 0.0500 mol

so, 0.0500 moles of H₂O produced

Volume of solution = 50.mL  +  50.mL  = 100.0 mL

Mass of solution m = volume × density = 100.0mL × 1.0 g/mL = 100 g

now ,

Heat energy of Solution q= (mass × specific heat capacity × temp Δ) + Cal

we know that; The specific heat of water(H₂O) is 4.18 J/g°C.

so we substitute

q_soln = (100g × 4.18 × ( 28.0 °C - 21.2 °C) ) + 1234.28

q_soln = 2842.4 + 1234.28

q_soln = 4076.68 J

Enthalpy change for the neutralization is ΔH_{neutralization}

ΔH_{neutralization} = -q_soln / mole of water produced

so we substitute

ΔH_{neutralization} = -( 4076.68 J ) / 0.0500 mol  

ΔH_{neutralization} = - 81533.6 J/mol

Therefore, the total change in enthalpy for the reaction is - 81533.6 J/mol

6 0
3 years ago
How can you tell if a chemical equation is balanced
k0ka [10]

Answer:

A chemical equation is balanced when the number of each kind of atom is the same on both sides of the reaction.

Explanation:

    The law of conservation of matter (except in nuclear reactions) indicates that atoms can neither be created or destroyed.

    The number of atoms that are in the  reactants must be the same as the number of the atoms that are in the product.

    The number and types of molecules can (and will) change. The atoms that make up the molecules are rearranged but the number and kinds of atoms stay the same.  

3 0
3 years ago
Carbon dioxide (CO2) is the gas that is mainly responsible for global warming (the greenhouse effect). The burning of fossil fue
Nesterboy [21]

Answer:

1.7\cdot 10^{15} g

Explanation:

Glucose reacts with oxygen do produce carbon dioxide and water:

C_6H_12O_6 (s) + 6 O_2 (g)\rightarrow 6 CO_2 (g) + 6 H_2O (l)

Given a daily mass of glucose:

m_1 = 5.0\cdot 10^2 g

Find moles of glucose:

n_1 = {5.0\cdot 10^2 g}{180.156 g/mol} = 2.775 mol

From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:

n_2 = 2.775 mol\cdot 6=16.65 mol

Convert this into mass using the molar mass of carbon dioxide:

m_2 = 16.65 mol\cdot 44.01 g/mol = 732.8 g

This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:

732.8 \frac{g}{person\cdot day}\cdot 365 days\cdot 6.5\cdot 10^9 people = 1.7\cdot 10^{15} g

5 0
3 years ago
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