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kari74 [83]
2 years ago
14

A randomly generated list of numbers from 0 to 4 is being used to simulate an event, with the number 4 representing a success. W

hat is the estimated probability of a success?
A.75%
B.60
C.25%
D.40%
Mathematics
1 answer:
sergey [27]2 years ago
6 0

The solution would be like this for this specific problem:

Given:

{0<span>, </span>1<span>, </span>2<span>, </span>3<span>, </span>4<span>}
</span>Success = 2, 3, and 4

 

Solution:

<span>Success = 3 numbers
Sample = 5

= 3 / 5</span>

= .6

= .6 * 100%

= 60%

So, the estimated probability of a success based from the randomly generated list of numbers being used to simulate an event is 60%.

 

 

To add, the measure of the likelihood that an event will occur is called probability<span> and it is quantified as a number between 0 and 1, where, loosely speaking, 0 indicates impossibility and 1 indicates certainty.</span>

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I need help ASAP! Can anyone please check my work?
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A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

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