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2 years ago

6

A 4.0 kg mass is attached to a spring whose spring constant is 950 N/m. It oscillates with an amplitude of 0.12 m. What is the m

aximum velocity of the mass

1 answer:

Fudgin [204]2 years ago

3 0

Answer:

velocity = 2.62m/s

Explanation:

950= (4 x A)/0.12

950 x 0.12 = 4 x A

114 = 4 x A

A = 114/4

A = 28.5m/s²

U²=2as
U² = 2 x 28.5 x 0.12
U² = 6.84
U = √6.84
U = 2.62m/s

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