In the figure a block slides along a track from one level to a higher level, by moving through an
1 answer:
Answer:
(B) 1.17 m.
Explanation:
At the highest point, the conservation of energy equation would becomes;
K.E (initial ) = K.E + P.E;
½ m(V)^2 = ½ m(V)^2 + mgh
(m*6^2)/2 = (m * 9.81 * 1.1) + (m*V^2)/2
36/2 = (9.81 * 1.1) + v^2/2
Solving the equation;
v=√14.44 m/s
= 3.8 m/s
a = −0.6g
= -0.6*9.81
= −5.88 m/s^2
Using equation of motion,
V^2 = U^2 + 2aS
S = V^2/2a
= 14.44/12
= 1.19 m.
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