Question

What is the electric potential difference of 5cm from a point charge of -2.0µc

Answer 1

Answer:

V = 360 kV

Explanation:

Given that,

Charge, q = -2µC

We need to find the electric potential difference of 5cm from a point charge.

We know that the formula for the electric potential is given by :

$V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 2\times 10^{-6}}{0.05}\\\\V=360000\ V$

or

$V=360\ kV$

So, the electric potential difference is 360 kV.