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aleksandrvk [35]
3 years ago
8

What is the mass in grams of a sample of 1.20 x 10 22 atoms of mercury?

Chemistry
2 answers:
lara [203]3 years ago
5 0
4.0g Hg. I may be wrong and I really don't remember how to do it so I am not going to tell you my work, but I tried because I never did good on the chapter in chem.
ArbitrLikvidat [17]3 years ago
5 0
The number of moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³] (which is used as a standard in the world of moles).

Now,

          if     6.02 × 10²³ atoms are found in 1 mole of mecury
   then let   1.20 × 10²² atoms are found in     x

⇒     x  =    (1.20 × 10²²)  ÷  (6.02 × 10²³)

            =  0.0199 moles

Now, mass = moles × molar mass

∴ mass of Hg = 0.0199 mol ×  201 g/mol
                      = 4.001 g

∴ T<span>he mass in grams of a sample of 1.20 x 10</span>²²<span> atoms of mercury is ~ 4 g</span>
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If the volume of a gas container at 32 degrees Celsius changes from 1.55 L to 755 mL, what will the final temperature be?
QveST [7]
So to solve this you need to know Charles’s law which is: V1/T1=V2/T2. Where T1 and V1 is the initial volume and Temperature and V2 and T2 is the temperature and volume afterwards. So first plug in the numbers you are given. V1= 1.55L T1= 32C° V2= 755mL T2=?. Since your volumes are two different units you change 755mL to be in L so that would be 0.755 L. And since your temp isn’t in Kelvin you do 273+32= 305K°. You then would rearrange your equation to solve for T2 which is V2T1/V1. Then you plug in your numbers (0.755L)(305K)/1.55L. Then you solve and would be 148.5645161 —> 1.49 x 10^2 K
4 0
3 years ago
What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?
White raven [17]

Answer:

36.8 L

Explanation:

We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 80 °C

T(K) = 80 + 273

T(K) = 353 K

Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:

Number of mole (n) = 1.27 moles

Temperature (T) = 353 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 1.27 × 0.0821 × 353

V = 36.8 L

Thus, the volume occupied by the helium gas is 36.8 L

5 0
3 years ago
Butanoic acid + 1-pentanol
lutik1710 [3]

Answer: X is an Esther

Explanation: alcohol and carboxylate acid forms esters

7 0
2 years ago
An 8 oz. bottle of energy drink contains 6.0 g of protein, 2.0 g of fat, and 16.3 g of carbohydrate. The fuel value of this ener
valina [46]

<u>Answer:</u> The correct option is d) 460 kJ

<u>Explanation:</u>

We are given:

Content of fat in energy drink = 2.0 g

Content of protein in energy drink = 6.0 g

Content of carbohydrate in energy drink = 16.3 g

Also,

The fuel value of fat = 38 kJ/g

The fuel value of protein = 17 kJ/g

The fuel value of carbohydrate = 17 kJ/g

So, the fuel value of the energy drink will be:

Total fuel value = (2.0g\times 38 kJ/g)+(6.0g\times 17 kJ/g)+(16.3g\times 17 kJ/g)

Total fuel value = [76+102+277]=460kJ

Hence, the correct option is d) 460 kJ

4 0
3 years ago
Convert 63.3 kg to grams
Zepler [3.9K]

Answer:

63300

Explanation:

63300

5 0
3 years ago
Read 2 more answers
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