Answer:
0.625 g
Explanation:
Given data:
Half life of radon-222 = 3.8 days
Total mass of sample = 10 g
Mass left after 15.2 days = ?
Solution:
Number of half lives = T elapsed / Half life
Number of half lives = 15.2 / 3.8
Number of half lives = 4
At time zero = 10 g
At first half life = 10 g/2 = 5 g
At 2nd half life = 5 g/ 2= 2.5 g
At third half life = 2.5 g/2 = 1.25 g
At 4th half life = 1.25 g/2 = 0.625 g
A. Strontium Phosphate
Solubility product constant is an equilibrium constant for the maximum amount of solute that can dissolve to form an aqueous solution. The value of the constant describes a solution which is saturated.
The greater the solubility product constant, the more soluble a solute is in the liquid. Consequently, the smaller the constant, the less soluble the solute is. The following list shows the solubility product constants of the given compounds in aqueous solutions at 298K in decreasing order:
Thallium Bromide - 3.71×10–6
Copper Iodide - 1.27×10<span>–12
</span>Silver Bromide - 5.35×10–13
Silver Arsenate - 1.03×10–22
Mercury Bromide - 6.40×10–23
Strontium Phosphate - 1×10–31
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The salt with the smallest solubility product constant is strontium phosphate, and therefore is the one which is least soluble in water.
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There are 26 electrons in the nickel ion in the compound NiS.
<h3>How many electrons does the nickel ion contain in the compound NiS?</h3>
The number of electrons in a neutral Nickel atom is obtained from the atomic number of Nickel.
The atomic number of Nickel is 28, therefore, the neutral nickel atom has 28 electrons.
In the compound NiS, nickel atom loses two electrons to to form the nickel ion.
Number of electrons left = 28 - 2 = 26
Therefore, there are 26 electrons in the nickel ion in the compound NiS.
In conclusion, nickel atom loses two electrons to form nickel ion in NiS.
Learn more about electrons at: brainly.com/question/860094
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Would be considered as an iconic bond.