Answer:
150 mL of the 30% alcohol mixture and 30 mL of the pure water will we need to obtain the desired solution.
Explanation:
Let the volume of 30% alcohol used to make the mixture = x L
For 25% alcohol:
C₁ = 25% , V₁ = 180 mL
For 30% alcohol :
C₂ = 30% , V₂ = x L
Using
C₁V₁ = C₂V₂
25×180 = 30×x
So,
x = 150 mL
Pure water = 180 mL - 150 mL = 30 mL
<u>150 mL of the 30% alcohol mixture and 30 mL of the pure water will we need to obtain the desired solution.</u>
A which is element is the answer
Answer:
c = 0.25 j/g.°C
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of metal = 50.0 g
Heat needed = 314 j
Initial temperature = 25°C
Final temperature = 50 °C
Specific heat = ?
Solution:
ΔT = 50 °C - 25°C = 25°C
Q = m.c. ΔT
c = Q / m. ΔT
c = 314 j / 50.0 g . 25°C
c = 314 j / 1250 g. °C
c = 0.25 j/g.°C
