Answer:
773.15K
Explanation:
Temperature is measured in different units, however, the standard or absolute temperature unit is Kelvin (K).
To convert the temperature of a black body, which is 500°C to Kelvin, we use;
T(K) = T(°C) + 273.15
T(K) = 500°C + 273.15
T(K) = 773.15K
Hence, the temperature of the blackbody at 500°C will be 773.15 K for it to radiate twice as much energy per second.
Answer:
Explanation:
We shall apply the theory of
heat lost = heat gained .
heat lost by water = mass x specific heat x temperature diff
= .285 x 4190 x ( 75.2 - 32 ) = 51587.28 J
heat gained by ice to attain temperature of zero
= m x 2100 x 22.8 = 47880 m
heat gained by ice in melting = latent heat x mass
= 334000m
heat gained by water at zero to become warm at 32 degree
= m x 4190 x 32 = 134080 m
Total heat gained = 515960 m
So
515960 m = 51587.28
m = .1 kg
= 100 gm
D. the last choice because the info above tells u so
Answer:
the volume will increase
Explanation:
if the temperature is held constant , the equation is reduced yo Boyle's law
