Answer: Here this will help you..
Explanation:
1 kg-m/s to kilogram-force meter/second = 1 kilogram-force meter/second
5 kg-m/s to kilogram-force meter/second = 5 kilogram-force meter/second
10 kg-m/s to kilogram-force meter/second = 10 kilogram-force meter/second
20 kg-m/s to kilogram-force meter/second = 20 kilogram-force meter/second
30 kg-m/s to kilogram-force meter/second = 30 kilogram-force meter/second
40 kg-m/s to kilogram-force meter/second = 40 kilogram-force meter/second
50 kg-m/s to kilogram-force meter/second = 50 kilogram-force meter/second
75 kg-m/s to kilogram-force meter/second = 75 kilogram-force meter/second
100 kg-m/s to kilogram-force meter/second = 100 kilogram-force meter/second
Answer:
1m= 3.2 feets
? = 5280 feets
let ? be n
cross multiply
3.2n = 1×5280
n= 5280÷3.2
n= 1650
so, 5280 feets is equal to 1650 metres
<span>Is more than one displacement possible?
No, displacement only considers the initial and final position.
Is more than one average velocity possible?
No, the average velocity is defined as displacement per time and since there is only one displacement possible, there is only one average velocity possible as well.
Is more than one average speed possible?
Yes, the average speed considers the total distance traveled and this distance may not be the same as the total displacement.
</span>
Answer:
Option B
Explanation:
The fundamental quantities are the basic quantities from which other quantities are derived.
There are a total of 7 fundamental quantities, namely Length, Mass, Time, Luminous Intensity, Amount of substance, Electric Current, Temperature.
From these 7 quantities, the other quantities are derived.
Weight is the product of its mass and the gravitational acceleration 'g' which acts on that mass.
Where mass is the fundamental quantity and 'g' is also derived and hence weight is a derived quantity.
By definition, the gravitational force is given by:

Where,
G: gravitational constant
m1: mass of object 1
m2: mass of object 2
r: distance between objects:
We know that the force is equal to 10N:

If the distance is double we have:


Therefore, the new force is:
2.5 newtons
Answer:
the changed force of attraction between them is:
A. 2.5 newtons