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MAVERICK [17]
3 years ago
15

Agent Hunt is transferring classified files from the CIA mainframe to his flash drive. The variable S models the size of the fil

es on the drive (in megabytes) after t seconds of transfer. S=5t+45 How many megabytes does Agent Hunt transfer every 10 seconds?
Mathematics
2 answers:
Komok [63]3 years ago
8 0

Answer:

50MB (MEGABITES)

amid [387]3 years ago
6 0

Answer:

<h2>50MB</h2>

Step-by-step explanation:

\bold{METHOD\ 1:}\\\\\text{Calculate the value of }S\ \text{in}\ 10s,\ 20s,\ 30s,\ ... \text{and difference if them}\\\\for\ t=10:\\\\S=5(10)+45=50+45=95\\\\for\ t=20:\\\\S=5(20)+45=100+45=145\\\\for\ t=30:\\\\S=5(30)+45=150+45=195\\\\195-145=50\\145-95=50\\\\\boxed{50\ MB\ per\ 10s}

\bold{METHOD\ 2:}\\\\S_1=5t+45\to \text{in t second}\\\\S_2=5(t+10)+45\to \text{10 second leter}\\\\\text{Difference}\\\\S_2-S_1=5(t+10)+45-(5t+45)=5t+50+45-5t-45=50\\\\\boxed{50MB\ per\ 10s}

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just olya [345]

Answer:

$5

Step-by-step explanation:

15x18=270

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4 0
3 years ago
Read 2 more answers
What is f(x) = –4x2 + 24x + 13 written in vertex form? f(x) = –4(x – 6)2 + 23 f(x) = –4(x – 6)2 + 7 f(x) = –4(x – 3)2 + 4 f(x) =
nika2105 [10]
We have that
f(x) = –4x²<span> + 24x + 13
</span>
we know that

The vertex form for a parabola that opens up or down is:

f(x) = a(x - h)^2 + k

in the given equation, <span>a=-4</span><span>, therefore we add zero to the original equation in the form of </span><span>4h</span>²<span>−4h</span>²
f(x) = –4x² + 24x + 4h²−4h² +13
<span>Factor 4 out of the first 3 terms and group them 
</span>f(x) = –4*(x² -6x +h²) +4h² +13
<span>We can find the value of h by setting the middle term equal to -2hx
</span>−2hx=−6x
<span>h=3</span><span> and  </span><span>4h</span>²<span>=<span>36
</span></span>f(x) = –4*(x² -6x +9) +36 +13

we know that the term (x² -6x +9) is equals to------> (x-3)²
so
f(x) = –4*(x-3)² +49

the answer is
f(x) = –4*(x-3)² +49

 

4 0
4 years ago
Which ordered pairs are solutions to the inequality 2y-x ≤ -6 ?
Inga [223]

Answer:

c (2, -2)

Step-by-step explanation:

5 0
3 years ago
Two alloys A and B are being used to manufacture a certain steel product. An experiment needs to be designed to compare the two
sveta [45]

Answer:

Step-by-step explanation:

From the given information, we can compute the table showing the summarized statistics of the two alloys A & B:

                                            Alloy A        Alloy B

Sample mean                    \bar {x} _A = 49.5      \bar {x} _B = 45.5

Equal standard deviation    \sigma_A = 5         \sigma_B= 5

Sample size                          n_A = 30        n_{B}= 30

Mean of the sampling distribution is :

\mu_{\bar{X_1}-\bar{X_2}}= 49.5-45.5  \\ \\ = 4.0

Standard deviation of sampling distribution:

\sigma_{\bar{x_1}-\bar{x_2} }= \sqrt{\sigma^2_{\bar{x_1}-\bar{x_2} }} \\ \\ = \sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma^2_2}{n_2} } \\ \\ =\sqrt{\dfrac{25}{30}+\dfrac{25}{30}} \\\\=\sqrt{1.667}  \\ \\ =1.2909

Hypothesis testing.

Null hypothesis:  H_o: \mu_A -\mu_B = 0

Alternative hypothesis:  H_A:\mu_A -\mu_B > 4

The required probability is:

P(\overline X_A - \overline X_B>4|\mu_A - \mu_B) = P\Big (\dfrac{(\overline X_A - \overline X_B)-\mu_{X_A-X_B}}{\sigma_{\overline x_A -\overline x_B}} > \dfrac{4 - \mu_{X_A-\overline X_B}}{\sigma _{\overline x_A - \overline X_B}}   \Big) \\ \\ = P \Big( z > \dfrac{4-0}{1.2909}\Big) \\ \\ = P(z \ge 3.10)\\ \\ = 1 - P(z < 3.10) \\ \\ \text{Using EXCEL Function:} \\ \\  = 1 - [NORMDIST(3.10)]  \\ \\ = 1- 0.999032 \\ \\ 0.000968 \\ \\ \simeq  0.0010

This implies that a minimal chance of probability shows that the difference of 4 is not likely, provided that the two population means are the same.

b)

Since the P-value is very small which is lower than any level of significance.

Then, we reject H_o and conclude that there is enough evidence to fully support alloy A.

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