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ivann1987 [24]
3 years ago
6

Two people are pushing on a desk to the right with a force 15n each what is the net force on the desk

Physics
1 answer:
dybincka [34]3 years ago
3 0
30N to the right direction
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A speaker is designed for wide dispersion for a high frequency sound. What should the diameter of the circular opening be for a
andriy [413]

To solve this problem we will apply the concepts related to wavelength, as well as Rayleigh's Criterion or Optical resolution, the optical limit due to diffraction can be calculated empirically from the following relationship,

sin\theta = 1.22\frac{\lambda}{d}

Here,

\lambda = Wavelength

d= Diameter of aperture

\theta = Angular resolution or diffraction angle

Our values are given as,

\theta = 11\°

The frequency of the sound is f = 9100 Hz

The speed of the sound is v = 343 m/s

The wavelength of the sound is

\lambda = \frac{v}{f}

Here,

v = Velocity of the wave

f = Frequency

Replacing,

\lambda = \frac{(343 m/s)}{(9100 Hz)}

\lambda = 0.0377 m

The diffraction condition is then,

sin\theta = 1.22\frac{\lambda}{d}

Replacing,

sin(11\°) = 1.22\frac{(0.0377 m)}{(d)}

d = 0.24 m

Therefore the diameter should be 0.24m

6 0
3 years ago
Use Hooke's Law to determine the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters.
ladessa [460]

Answer:

Work Done = 67.5 J

Explanation:

First we find the value of spring constant (k) using Hooke's Law. Hooke's is formulated as:

F = kx

where,

F = Force Applied = 450 N

k = Spring Constant = ?

x = Stretched Length = 30 cm = 0.3 m

Therefore,

450 N = k(0.3 m)

k = 450 N/0.3 m

k = 1500 N/m

Now, the formula for the work done in stretching the spring is given as:

W = (1/2)kx²

Where,

W = Work done = ?

k = 1500 N/m

x = 70 cm - 40 cm = 0.3 m

Therefore,

W = (1/2)(1500 N/m)(0.3 m)²

<u>W = 67.5 J</u>

3 0
2 years ago
If 478 watts of power are used in 14 seconds, how much work was done?
sergiy2304 [10]
" 478 watts " means 478 joules per second.

In 14 seconds, the total work or energy is (14 x 478) = <em>6,692 joules</em>
7 0
3 years ago
What are 2 examples of Newton's second law in everyday life?
IRISSAK [1]

Answer:

kicking ball and throwing stone

5 0
2 years ago
Read 2 more answers
The velocity of a ball as it is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average a
ArbitrLikvidat [17]
Acceleration = (final velocity - initial velocity) / time
Acceleration = 20 - 0 / 3.5
= 5.714 m/s^2

Hope it helped!
8 0
3 years ago
Read 2 more answers
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