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ivann1987 [24]
3 years ago
6

Two people are pushing on a desk to the right with a force 15n each what is the net force on the desk

Physics
1 answer:
dybincka [34]3 years ago
3 0
30N to the right direction
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Adhesion is when forces of the molecules are more strongly drawn to each other than the molecules in other substances true or fa
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Answer:

False

Explanation:

that is cohesion. adhesion is force between dissimilar molecules of a body

6 0
3 years ago
Iii A load of 2.5 N is hung on the spring.
Anna11 [10]
N stands for Newton
2- upload the graph..
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3 years ago
What is the oxidation number of the element Se
maria [59]

Answer:

The oxidation number of a monatomic (composed of one atom) ion is the same as the charge of the ion. For example, the oxidation numbers of K+, Se2−, and Au3+ are +1, -2, and +3, respectively. The oxidation number of oxygen in most compounds is −2.

Explanation:

6 0
2 years ago
A mass of 0.450 kg rotates at constant speed with a period of 1.45 s at a radius R of 0.140 m in the apparatus used in this labo
Mamont248 [21]

Answer:

1.603 s

Explanation:

Given that

Initial mass, = 0.45 kg

Initial period, = 1.45 s

Initial radius, = 0.14 m

Final mass, = 0.55 kg

Final period, = ?

Final radios, = 0.14 m

Since we are finding the rotation period of two masses of same radius, we can assume that the outward force is the same in both cases. This means that

m₁r₁ω₁² = m₂r₂ω2²

Where, ω = 2π/T, on substituting, we have

0.45 * 0.14 * (2π / 1.45)² = 0.550 * 0.14 * (2π / T₂)²

0.45 / 1.45² = 0.550 / T₂²

T₂² = 0.550 * 1.45² / 0.45

T₂² = 2.56972

T₂ = √2.56972

T₂ = 1.603 sec

7 0
3 years ago
An electric dipole consists of charges +2e and -2e separated by 0.82 nm. It is in an electric field of strength 3.2 x 10^6 N/C.
Zepler [3.9K]

Explanation:

It is given that,

An electric dipole consists of charges +2e and -2e separated by 0.82 nm

Charge, q=2e=2\times 1.6\times 10^{-19}\ C=3.2\times 10^{-19}\ C

Distance between charges, d=0.82\ nm=0.82\times 10^{-9}\ m

Electric field strength, E=3.2\times 10^6\ N/C

(a) The magnitude of the torque on the dipole is given by :

\tau=p\times E\ sin\theta

When dipole moment is parallel to the electric field, \theta=0

\tau=p\times E\ sin(0)

\tau=0

(b) When the dipole is perpendicular to the electric field, \theta=90

\tau=pE\ sin(90)

\tau=qdE (Since, p = q × d)

\tau=3.2\times 10^{-19}\times 0.82\times 10^{-9}\times 3.2\times 10^6

\tau=8.39\times 10^{-22}\ N.m

(c) When the dipole moment is anti parallel to the electric field, \theta=180

\tau=pE\ sin(180)

Since, sin\ 180=0

\tau=0

Hence, this is the required solution.

8 0
3 years ago
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