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vampirchik [111]
2 years ago
12

Which of the following is incorrect for nuclear forces

Physics
2 answers:
densk [106]2 years ago
4 0

Answer:

c they obey inverse square law

bija089 [108]2 years ago
4 0
Answer is C .

The reason is as follows:
Nuclear forces don’t obey inverse square law.

Neither the strong nuclear force nor the weak nuclear force follow the inverse square law.

The weak nuclear force is a Yukawa-type force. Such a force is characterized by a potential in the form ∝−/
∝
e
−
m
r
/
r
. At short range ( ≪1
m
r
≪
1
) the exponential term is just 1
1
, so the potential becomes an inverse-
r
potential with an inverse square force law associated with it. So at very short (subatomic) ranges, the weak nuclear force is actually very similar to the electromagnetic force. But as soon as >1
m
r
>
1
, the force rapidly vanishes and becomes undetectable.

The strong nuclear force does not decrease with distance. Which means that as you “stretch” the bond between two quarks, for instance, more and more energy needs to be invested; until there is enough energy to create a new quark-antiquark pair, at which point the bond breaks. This limits the range of the strong nuclear force to subatomic scales, too.
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Makovka662 [10]
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Earth > Biosphere > Biome > Ecosystem > Community > Population > Organism > Organelles 

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7 0
3 years ago
A satellite is orbiting Earth with a distance R = 2REarth from Earth's center. If the satellite is moved to a distance R = 4REar
Maslowich

Answer:

Half

Explanation:

Given that:

  • radial distance of satellite from the earth, R=2R_E

Now, if the satellite is moved to a distance R=4R_E

<u>We  have the mathematical expression for the potential energy fue to gravitational field as:</u>

U=\frac{G.M.m}{R} ...................(1)

where:

G = 6.67\times 10^{-11}\ m^3.kg^{-1}.s^{2}

M = mass of earth

m = mass of satellite

R = radial distance of satellite

<u>Now from eq. (1) initially we have:</u>

U=\frac{G.M.m}{2R_E}

<u>after the satellite is moved, we have:</u>

U'=\frac{G.M.m}{4R_E}

\Rightarrow U'=\frac{G.M.m}{2(2R_E)}

\Rightarrow U'=\frac{1}{2} \times U

which is half of the initial condition.

3 0
3 years ago
Use correct alternative to complete the indirect speech sentence​
alexandr1967 [171]

Answer:

where a picture

Explanation:

a saan Ang picture

3 0
2 years ago
What conditions must be met in order for work to be done?
Mashcka [7]

Answer:

i think the answer is D

Explanation:

srry if im wrong

4 0
2 years ago
A particle moves along a straight line and its position at time t is given by
Alisiya [41]

(A) Use interval notation to indicate the time interval or union of time intervals when the particle is moving forward and backward

the particle is speeding up

<span>if  a(t) >0, it means 12t-48>0, and t >4,  I = ]4, infinity[</span>

the particle is speeding down

<span>if  a(t) < 0, it means 12t-48>0, and t < 4,  I = ] -infinity, 4[</span>

 

when the particle is moving forward and backward

that is depending of the sign of v(t)

moving forward if v(t)> 0

<span>moving backward if v(t)<  0</span>

but v(t) = 6t² - 48 t +90, this quadratic equation has exactly two solutions, t =1, and t =3

<span>so  after taking care the sign of </span>6t² - 48 t +90,

 

<span>v(t)> o when  t is in I = ] –inf, 1[ U ]4, inf[,the particle is moving forward</span>

<span>v(t) < o when  t is in I = ]1, 4[,the particle is moving backward</span>

<span> </span>

3 0
3 years ago
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