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2 years ago

Which of the following is incorrect for nuclear forces

Physics

2 answers:

densk [106]2 years ago

4 0

Answer:

c they obey inverse square law

bija089 [108]2 years ago

4 0

Answer is C .

The reason is as follows:
Nuclear forces don’t obey inverse square law.

Neither the strong nuclear force nor the weak nuclear force follow the inverse square law.

The weak nuclear force is a Yukawa-type force. Such a force is characterized by a potential in the form ∝−/
∝
e
−
m
r
/
r
. At short range ( ≪1
m
r
≪
1
) the exponential term is just 1
1
, so the potential becomes an inverse-
r
potential with an inverse square force law associated with it. So at very short (subatomic) ranges, the weak nuclear force is actually very similar to the electromagnetic force. But as soon as >1
m
r
>
1
, the force rapidly vanishes and becomes undetectable.

The strong nuclear force does not decrease with distance. Which means that as you “stretch” the bond between two quarks, for instance, more and more energy needs to be invested; until there is enough energy to create a new quark-antiquark pair, at which point the bond breaks. This limits the range of the strong nuclear force to subatomic scales, too.

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3 years ago

A Hall probe, consisting of a rectangular slab of current-carrying material, is calibrated by placing it in a known magnetic fie

Citrus2011 [14]

Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, $V_{Hall} = 20\ mV = 0.02\ V$

Magnetic Field, B = 0.10 T

Hall emf, $V'_{Hall} = 69\ mV = 0.069\ V$

Now,

Drift velocity, $v_{d} = \frac{V_{Hall}}{B}$

$v_{d} = \frac{0.02}{0.10} = 0.2\ m/s$

Now, the expression for the electric field is given by:

$E_{Hall} = Bv_{d}sin\theta$ (1)

And

$E_{Hall} = V_{Hall}d$

Thus eqn (1) becomes

$V_{Hall}d = dBv_{d}sin\theta$

where

d = distance

$B = \frac{V_{Hall}}{v_{d}sin\theta}$ (2)

(a) When $\theta = 90^{\circ}$

$B = \frac{0.069}{0.2\times sin90} = 0.345\ T$

(b) When $\theta = 60^{\circ}$

$B = \frac{0.069}{0.2\times sin60} = 0.398\ T$

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2 years ago

What is the momentum of a 1200 kg car traveling with a speed of 27 m/s (60 mph)?

serious [3.7K]

Answer:

This is your answer

Explanation:

Actually I took this from go ogle

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2 years ago

Mrs. Roberts' class was designing science experiments. Carl and his partner decided to use the outdoor classroom as their labora

Contact [7]

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3 years ago

When passing through a lock, which light means âapproach the lock under full control?â?

vekshin1

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2 years ago